我使用pymongo在集合中插入一个复杂的结构作为行。该结构是字典列表等的字典列表的字典。
有没有办法找到导致错误的字段是unicode而不是str?我试过:
def dump(obj):
with open('log', 'w') as flog:
for attr in dir(obj):
t, att = type(attr), getattr(obj, attr)
output = "obj.%s = %s" % (t, att)
flog.write(output)
但到目前为止运气不佳。
有什么聪明的递归方式可以打印所有内容吗?
感谢
下面的内容帮助我找出了哪个dict包含unicode值,因为dict可以通过其键来识别。列表案例没有帮助。
def find_the_damn_unicode(obj):
if isinstance(obj, unicode):
''' The following conversion probably doesn't do anything meaningfull since
obj is probably a primitive type, thus passed by value. Thats why encoding
is also performed inside the for loops below'''
obj = obj.encode('utf-8')
return obj
if isinstance(obj, dict):
for k, v in obj.items():
if isinstance(v, unicode):
print 'UNICODE value with key ', k
obj[k] = obj[k].encode('utf-8')
else:
obj[k] = find_the_damn_unicode(v)
if isinstance(obj, list):
for i, v in enumerate(obj):
if isinstance(v, unicode):
print 'UNICODE inside a ... list'
obj[i] = obj[i].encode('utf-8')
else:
obj[i] = find_the_damn_unicode(v)
return obj