如何替换:
<tag attr="z">
<tag attr="y">
<tag attr="x"></tag>
</tag>
</tag>
至:
<tag attr="z">
[tag=y]
<tag attr="x"></tag>
[/tag]
</tag>
不使用扩展?
我尝试失败:
preg_replace("#<tag attr="y">(.+?)</tag>#i", "[tag=y]\1[/tag]", $text);
PHP的regex实现支持PCRE的递归模式。然而,我会犹豫是否使用这样的功能,因为它具有神秘的性质。然而,既然你问:
不使用扩展?
在这里:
<?php
$html = '<tag attr="z">
<tag attr="y">
<tag>
<tag attr="more" stuff="here">
<tag attr="x"></tag>
</tag>
</tag>
</tag>
</tag>
';
$attr_regex = "(?:s+w+s*=s*(?:'[^']*'|"[^"]*"))";
$recursive_regex = "@
<tags+attr="y"> # match opening tag with attribute 'y'
( # start match group 1
s* # match zero or more white-space chars
<(w+)$attr_regex*\s*> # match an opening tag and store the name in group 2
( # start match group 3
[^<]+ # match one or more chars other than '<'
| # OR
(?1) # match whatever the pattern from match group 1 matches (recursive call!)
)* # end match group 3
</\2> # match the closing tag with the same name stored in group 2
s* # match zero or more white-space chars
) # end match group 1
</tag> # match closing tag
@x";
echo preg_replace($recursive_regex, "[tag=y]$1[/tag]", $html);
?>
它将打印以下内容:
<tag attr="z">
[tag=y]
<tag>
<tag attr="more" stuff="here">
<tag attr="x"></tag>
</tag>
</tag>
[/tag]
</tag>