通过反射创建表达式<Func<T、对象>>变量

Question

我创建了以下类：

public class Person
{
     public string FirstName { get; set; }
     public string LastName { get; set; }
}

我可以将以下语句设置为方法参数：

myClass.SetFieldName<Person>(p => p.LastName);

参数类型为：

Expression<Func<Person, object>>

现在，我试图实现的是为通过反射找到的属性调用SetFieldName方法。想象一下，我有一个PropertyInfo（Person.LastName）的实例。我试图使用它的Lambda方法创建表达式，但失败了。

如果你能帮我的话，那就太好了。

谨致问候，Koray

Answer 1

您只需要稍微扩展一下flem的答案：

using System;
using System.Linq.Expressions;
using NUnit.Framework;
public class Person
{
    public string FirstName { get; set; }
    public string LastName { get; set; }
}
public static class ExpressionBuilder
{
    public static Expression<Func<TClass, TProperty>> Build<TClass, TProperty>(string fieldName)
    {
        var param = Expression.Parameter(typeof(TClass));
        var field = Expression.PropertyOrField(param, fieldName);
        return Expression.Lambda<Func<TClass, TProperty>>(field, param);
    }
}
[TestFixture]
public class Test
{
    [Test]
    public void TestExpressionBuilder()
    {
        var person = new Person { FirstName = "firstName", LastName = "lastName" };
        var expression = ExpressionBuilder.Build<Person, string>("FirstName");
        var firstName = expression.Compile()(person);
        Assert.That(firstName, Is.EqualTo(person.FirstName));
    }
}

Answer 2

// reflected field name
string fieldName = "LastName";
// create the parameter of the expression (Person)
ParameterExpression param = Expression.Parameter(typeof(Person), string.Empty);
// create the expression as a get accessor of a particular 
// field of the parameter (p.LastName)
Expression field = Expression.PropertyOrField(param, fieldName);

Answer 3

public static class LambdaExpressionExtensions
{
    public static Expression<Func<TInput, object>> ToUntypedPropertyExpression<TInput, TOutput> (this Expression<Func<TInput, TOutput>> expression)
    {
        var memberName = ((MemberExpression)expression.Body).Member.Name;
        var param = Expression.Parameter(typeof(TInput));
        var field = Expression.Property(param, memberName);
        return Expression.Lambda<Func<TInput, object>>(field, param);
    }
}