我有如下json,
{
"H": "Macellum",
"M": "Receive",
"A": [
{
"CustomerId": "172600",
"OrderId": "69931",
"OrderStatus": "E0",
"Buy": "A"
}
]
}
和复杂类型
public class OrderStats
{
public string CustomerId { get; set; }
public string OrderId { get; set; }
public string OrderStatus { get; set; }
public string Buy { get; set; }
}
我正在尝试如下选角,
dynamic obj = JsonConvert.DeserializeObject<dynamic>(message);
OrderStats info = (OrderStats)obj.A[0]; //exception
OrderStats info = obj.A[0] as OrderStats; //info is null
但错误如下
无法将类型"Newtonsoft.Json.Linq.JObject"转换为 OrderStatus
这个怎么样?
var str = "YOUR_JSON_HERE";
var obj = JsonConvert.DeserializeObject<dynamic>(str);
OrderStats info = ((JArray)obj.A)[0].ToObject<OrderStats>();
我发现像这样的解决方案有点微不足道,
dynamic obj = JsonConvert.DeserializeObject<dynamic>(message);
OrderStats info = JsonConvert.DeserializeObject<OrderStats>(JsonConvert.SerializeObject(obj.A[0]));
我正在审查此解决方案,但我认为没有必要使用动态键,
我这样做了,它对我来说是工作:
OrderStats info = JsonConvert.DeserializeObject(str(
它简化了您提到的其他行,但感谢您的建议,它是
对我正确
string jsonString = "{"name": "John Doe", "age": 30, "email": "johndoe@example.com"}";
// Parse the JSON string into a JObject
JObject jsonObject = JObject.Parse(jsonString);
// Convert the JObject into a complex type object
var person = jsonObject.ToObject<Person>();