BASH拆分字符串到自己的输出

Question

如何分割这个字符串

22:45:47.349293 00:00:00:00:00:00> 20:cf:30:39:60:69, ethertype IPv4 (0x0800)，长度342:192.168.0.1> 192.168.0.100.68:BOOTP/DHCP, Reply，长度300

变成一行

TIME FIRSTMACADDRESS firstp

22:45:47 00:00:00:00:00 192.168.0.1

?

我的实际结果是

时间:22:45:47

MAC: 00:c0:26:00:bc:14 IP: 192.168.0.1

的代码

    cat $TEMPDATA | while read line
    do
    if [ "$line" != "" ]; then
    set -- $line
    echo TIME: "$line" | awk -F '[.]' '{print $1}'
    echo MAC: "$2" IP: "$10"
    echo

    fi
    done

Answer 1

这在bash中很容易做到。这是快速和有效的:

#!/bin/bash
string="22:45:47.349293 00:00:00:00:00:00 > 20:cf:30:39:60:69, ethertype IPv4 (0x0800), length 342: 192.168.0.1 > 192.168.0.100.68: BOOTP/DHCP, Reply, length 300"
time="${string%%.*}"
tmp="${string#* }"
mac="${tmp%% *}"
tmp="${string% >*}"
ip="${tmp##*: }"
echo "time: '$time', mac: '$mac', ip: '$ip'"

输出:

time: '22:45:47', mac: '00:00:00:00:00:00', ip: '192.168.0.1'