我有一个来自YouTube API的JSON。
这是我在这个链接中的JSON
我无法从中获取图像。我无法显示图像。
我尝试了大约10天,但我解决不了这个问题。有人能解决这个问题吗
这是我的完整代码:
public class MainActivity extends ActionBarActivity {
// Declare Variables
JSONObject jsonobject;
JSONArray jsonarray;
ListView listview;
ListViewAdapter adapter;
ProgressDialog mProgressDialog;
ArrayList<HashMap<String, String>> arraylist;
static String imgURL = "https://i.ytimg.com/vi/uU-uRElXM3A/default.jpg";
static String VIDEO_ID = "videoId";
static String TITLE = "title";
//static String DESCRIPTION = "description";
static String THUMBNAILS = "thumbnails";
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
// Get the view from listview_main.xml
setContentView(R.layout.listview_main);
// Execute DownloadJSON AsyncTask
new DownloadJSON().execute();
}
// DownloadJSON AsyncTask
private class DownloadJSON extends AsyncTask<Void, Void, Void> {
@Override
protected void onPreExecute() {
super.onPreExecute();
// Create a progressdialog
mProgressDialog = new ProgressDialog(MainActivity.this);
// Set progressdialog title
mProgressDialog.setTitle("Your Youtube Video is");
// Set progressdialog message
mProgressDialog.setMessage("Loading...");
mProgressDialog.setIndeterminate(false);
// Show progressdialog
mProgressDialog.show();
}
@Override
protected Void doInBackground(Void... params) {
// Create an array
arraylist = new ArrayList<HashMap<String, String>>();
// Retrieve JSON Objects from the given URL address
jsonobject = JSONfunctions.getJSONfromURL("https://www.googleapis.com/youtube/v3/search?part=id%2Csnippet&q=natok+2015&maxResults=50&key=AIzaSyCojCp66RLS9OY8hOwnW0UWLNdC56z24Os");
try {
// Locate the array name in JSON
JSONArray jsonarray = jsonobject.getJSONArray("items");
for (int i = 0; i < jsonarray.length(); i++) {
HashMap<String, String> map = new HashMap<String, String>();
jsonobject = jsonarray.getJSONObject(i);
// Retrive JSON Objects
JSONObject jsonObjId = jsonobject.getJSONObject("id");
map.put("videoId", jsonObjId.getString("videoId"));
JSONObject jsonObjSnippet = jsonobject.getJSONObject("snippet");
map.put("title", jsonObjSnippet.getString("title"));
//JSONObject jsonObjThumbnail = jsonObjSnippet.getJSONObject("thumbnails");
// String imgURL = jsonobject.getJSONObject("thumbnails").getString("url"); //use "medium/high" instead of default as required.
JSONObject jsonObjThumbnail = jsonobject.getJSONObject("thumbnails");
String imgURL = jsonobject.getJSONObject("default").getString("url");
// Set the JSON Objects into the array
arraylist.add(map);
}
} catch (JSONException e) {
Log.e("Error", e.getMessage());
e.printStackTrace();
}
return null;
}
@Override
protected void onPostExecute(Void args) {
// Locate the listview in listview_main.xml
listview = (ListView) findViewById(R.id.listview);
// Pass the results into ListViewAdapter.java
adapter = new ListViewAdapter(MainActivity.this, arraylist);
// Set the adapter to the ListView
listview.setAdapter(adapter);
// Close the progressdialog
mProgressDialog.dismiss();
}
}
要从JSON中获取图像URL,请使用以下代码:线路JSONObject jsonObjSnippet = jsonobject.getJSONObject("snippet");
之后
JSONObject jsonObjThumbnail = jsonobject.getJSONObject("thumbnails");
String imgURL = jsonObjThumbnail.getJSONObject("default").getString("url");//use "medium/high" instead of default as required.
map.put("url", imgURL);
更新:您将获得字符串形式的imgURL;例如:https://i.ytimg.com/vi/uU-uRElXM3A/default.jpg
我想你忘了在"地图"中添加imageURL,
要解析json,您应该首先通过以下操作定义JSONArray对象:
JSONArray jsonArray = new JSONArray(jsonArrayString);
然后,您需要在整个json数组中循环以构建一个:
JSONArray jsonArray = jsnobject.getJSONArray("array-key");
for (int i = 0; i < jsonArray.length(); i++) {
JSONObject newObj = jsonArray.getJSONObject(i);
}