我有以下类定义:
public class ElasticObject : Dictionary<string, object>
{
public int Id { get;set;}
}
var keyValues = new ElasticObject();
keyValues.Id= 200000;
keyValues.Add("Price", 12.5);
var json = JsonConvert.SerializeObject(keyValues,
new JsonSerializerSettings{NullValueHandling = NullValueHandling.Ignore});
解析后的json字符串为{"Price":12.5},没有包含Id属性,有没有办法自定义json转换?
您可以通过创建自定义JsonConverter
类来实现这一点。也许是这样的:
class ElasticObjectConverter : JsonConverter
{
public override bool CanConvert(Type objectType)
{
return (objectType == typeof(ElasticObject));
}
public override void WriteJson(JsonWriter writer, object value, JsonSerializer serializer)
{
ElasticObject eobj = (ElasticObject)value;
var temp = new Dictionary<string, object>(eobj);
temp.Add("Id", eobj.Id);
serializer.Serialize(writer, temp);
}
public override object ReadJson(JsonReader reader, Type objectType, object existingValue, JsonSerializer serializer)
{
var temp = serializer.Deserialize<Dictionary<string, object>>(reader);
ElasticObject eobj = new ElasticObject();
foreach (string key in temp.Keys)
{
if (key == "Id")
eobj.Id = Convert.ToInt32(temp[key]);
else
eobj.Add(key, temp[key]);
}
return eobj;
}
}
然后你会这样使用它:
var settings = new JsonSerializerSettings
{
NullValueHandling = NullValueHandling.Ignore,
Converters = new List<JsonConverter> { new ElasticObjectConverter() }
};
var keyValues = new ElasticObject();
keyValues.Id = 200000;
keyValues.Add("Price", 12.5);
var json = JsonConvert.SerializeObject(keyValues, settings);
上面生成的JSON如下所示:
{"Price":12.5,"Id":200000}
这就是你要找的吗?
我让额外的属性只是将数据戳回基本字典。通过这种方式,您可以公开像"Id"这样的属性,但在序列化/去序列化过程中,它只能与底层字典一起工作:
public class ElasticObject : Dictionary<string, object>
{
public int Id
{
get {
int val;
if (int.TryParse(this["Id"] as string, out val))
{
return val;
}
return -1;
}
set { this["Id"] = value; }
}
}