我有两个这样的case类。
case class Company(name: String, address: Address)
case class Address(address1: String, address2: String,
city: String, state: String,
zip:String, country: String)
在我的应用程序。我定义了以下代码。
[1]. val companyForm = Form(of(Company.apply _, Company.unapply _)(
"name" -> text,
"address" -> mapping(
"address1" -> nonEmptyText,
"address2" -> text,
"city" -> nonEmptyText,
"state" -> nonEmptyText,
"zip" -> nonEmptyText,
"country" -> nonEmptyText
)(Address.apply)(Address.unapply)
)
)
[2]. val companyForm = Form(mapping(
"name" -> text,
"address" -> mapping(
"address1" -> nonEmptyText,
"address2" -> text,
"city" -> nonEmptyText,
"state" -> nonEmptyText,
"zip" -> nonEmptyText,
"country" -> nonEmptyText
)(Address.apply)(Address.unapply)
)(Company.apply, Company.unapply)
)
现在[1]为我工作,但当我试图将其转换为[2]时,它给了我以下错误:
方法映射参数太多:(apply: (String, models.Address) => R)(unapply: R => Option[(String, models.Address)])play.api.data.Mapping[R].
请告诉我哪里做错了。
由于methode of()
是贬义的,您的表单必须看起来像这样:
val companyForm = Form(
mapping(
"name" -> text,
"address" -> mapping(
"address1" -> nonEmptyText,
"address2" -> text,
"city" -> nonEmptyText,
"state" -> nonEmptyText,
"zip" -> nonEmptyText,
"country" -> nonEmptyText
)(Address.apply)(Address.unapply)
)(Company.apply)(Company.unapply)
)
所以你的问题是在下面的语法Company.Apply and Company.unapply
方法