我正试图为具有$rootScope.$on('accountsSet', function (event)...
的控制器编写一个测试。所以在测试中,我使用了.broadcast.andCallThrough()
,这是So中的许多其他问题建议的,而它以前也适用于我
所以我的控制器很简单:
角度模块("控制器侧菜单",[])
.controller('SidemenuCtrl', function($rootScope, $scope, AccountsService) {
$rootScope.$on('accountsSet', function (event) {
$scope.accounts = AccountsService.getAccounts();
$scope.pro = AccountsService.getPro();
});
});
任何测试都很简单:
describe("Testing the SidemenuCtrl.", function () {
var scope, createController, accountsService;
beforeEach(function(){
angular.mock.module('trevor');
angular.mock.module('templates');
inject(function ($injector, AccountsService) {
scope = $injector.get('$rootScope');
controller = $injector.get('$controller');
accountsService = AccountsService;
createController = function() {
return controller('SidemenuCtrl', {
'$scope' : $injector.get('$rootScope'),
'AccountsService' : accountsService,
});
};
});
});
it("Should load the SidemenuCtrl.", function () {
accountsService.setPro(true);
spyOn(scope, '$broadcast').andCallThrough();
var controller = createController();
scope.$broadcast("accountsSet", true);
expect(scope.pro).toBeTruthy();
});
});
对于spyOn(scope, '$broadcast').andCallThrough();
,我得到的错误。注意,这个测试的范围是rootScope
,所以这应该不是问题。
因此,引用该行的错误:TypeError:"undefined"不是函数(正在计算"spyOn(scope,'$broadcast').andCallThrough()")在/tests/controllers/sidemenu.js:30
我要把我的评论变成一个答案,因为它原来是解决方案:
在jasmine 2.0中,间谍的语法发生了变化(还有许多其他内容,请参阅此处的漂亮文档)新语法是
spyOn(foo, 'getBar').and.callThrough();
与:的jasmine 1.3语法进行比较
spyOn(foo, 'getBar').andCallThrough();