字符串对象无法在特定对象C＃中进行序列化

Question

1. 以字符串格式序列化数据

string data = "{"VerifyOTPResult":{"ReturnCode":"200","ReturnMsg":"Invalid OTP.","Data":{"BrokerName":null,"ErrorMsg":null,"Id":null,"IsValidUser":false,"RoleName":null}}}";

2. 对象类

public class VerifyOTPResult {
  public string ReturnCode { get; set; }
  public string ReturnMsg { get; set; }
  public ValidateUserResult Data { get; set; }
}
public class ValidateUserResult {
  public string Id { get; set; }
  public bool IsValidUser { get; set; }
  public string BrokerName { get; set; }        
  public string RoleName { get; set; }
  public string ErrorMsg { get; set; }
}

3. 使用newtonsoft.json组装用于DeserializeObject尝试1：

var decRes = JsonConvert.DeserializeObject<VerifyOTPResult>(content);

输出除了int属性

以外，在每个属性中获取null

尝试2：

var decRes1 = JsonConvert.DeserializeObject(content);

输出

{
    "VerifyOTPResult": {
        "ReturnCode": "200",
        "ReturnMsg": "Invalid OTP.",
        "Status": null,
        "CurrentPage": 0,
        "Data": {
            "BrokerName": null,
            "ErrorMsg": null,
            "Id": null,
            "IsValidUser": false,
            "RoleName": null
        }
    }
}

我无法避免。如何将其转换为我的对象类？

Answer 1

您的JSON包括VerifyOTPResult，但实际上是具有VerifyOTPResult属性的A 不同的对象。您应该对某些包装类别（即VerifyOTPResultResponse）

进行挑选

void Main()
{
    string data = "{"VerifyOTPResult":{"ReturnCode":"200","ReturnMsg":"Invalid OTP.","Data":{"BrokerName":null,"ErrorMsg":null,"Id":null,"IsValidUser":false,"RoleName":null}}}";
    var decRes = JsonConvert.DeserializeObject<VerifyOTPResultResponse>(data);
    Console.WriteLine(decRes.VerifyOTPResult.ReturnCode);
    Console.WriteLine(decRes.VerifyOTPResult.ReturnMsg);
    // Output:
    // 200
    // Invalid OTP.
}
public class VerifyOTPResultResponse
{
    public VerifyOTPResult VerifyOTPResult { get; set; }
}
public class VerifyOTPResult
{
    public string ReturnCode { get; set; }
    public string ReturnMsg { get; set; }
    public ValidateUserResult Data { get; set; }
}
public class ValidateUserResult
{
    public string Id { get; set; }
    public bool IsValidUser { get; set; }
    public string BrokerName { get; set; }
    public string RoleName { get; set; }
    public string ErrorMsg { get; set; }
}

Answer 2

yo可能会尝试serializer.Deserialize<MyObj>(str);以e.g var result=JsonConvert.DeserializeObject<List<yourObj>>(jsonString);