当RSS feed在PHP上更改时，如何播放声音

Question

我有这个php，它为经济新闻加载了RSS Feed。当RSS提要增加新标题时，是否可以播放声音？我还没有尝试任何事情，因为我不知道该怎么做。我想我需要做的是将变量从标题存储，然后比较它，然后在JavaScript上调用函数以播放声音。

<?php
$rss = new DOMDocument();
$rss->load('https://rss.dailyfx.com/feeds/alerts/');
$feed = array();
foreach ($rss->getElementsByTagName('item') as $node) {
$item = array ( 
'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
'date' => $node->getElementsByTagName('pubDate')->item(0)->nodeValue,
        );
    array_push($feed, $item);
}
    $limit = 5;
    for($x=0;$x<$limit;$x++) {
    $title = str_replace(' & ', ' &amp; ', $feed[$x]['title']);
    $description = $feed[$x]['desc'];
    $date = date('l F d, Y, H:m', strtotime($feed[$x]['date']));
    echo '<p><strong><a " title="'.$title.'">'.$title.'</a></strong><br />';
    echo '<small><em style="color:red; text-align:center;"> '.$date.'</em>    </small></p>';
    }
?>

Answer 1

我知道的一种方式是使用jquery/ajax确保您的目录中有jQuery文件 jquery.min.js 。我还修改了您的PHP代码以使其正常工作。让我知道您是否有任何问题。

<script src="jquery.min.js"></script>
<script type="text/javascript">
    $(document).ready(function(){
        //$('#submit').click(function(){
var title='rssfeed';
    $('#loader').fadeIn(400).html('<span>Please Wait, loading.....</span>');
//you can send data if you like
    var datasend = "title="+ title;
            $.ajax({
                type:'POST',
                url:'rssfeed.php',
                data:datasend,
                crossDomain: true,
                cache:false,
                success:function(msg){
    if(msg=='success'){
    alert('message successfully loaded');
(new Audio('https://notificationsounds.com/soundfiles/8b16ebc056e613024c057be590b542eb/file-sounds-1113-unconvinced.mp3')).play();
    }else{
alert('message loading failed');
}
                    $('#loader').hide();

                }
            });

        //})
    });

    </script>

//Display a loading message...
<div id="loader"></div>

您的php代码变为

<?php
// ensure there is no error message
error_reporting(0);
$rss = new DOMDocument();
$rss->load('https://rss.dailyfx.com/feeds/alerts/');
$feed = array();
foreach ($rss->getElementsByTagName('item') as $node) {
$item = array ( 
'title' => $node->getElementsByTagName('title')->item(0)->nodeValue,
'date' => $node->getElementsByTagName('pubDate')->item(0)->nodeValue,
        );
    array_push($feed, $item);
}
    $limit = 5;
    for($x=0;$x<$limit;$x++) {
    $title = str_replace(' & ', ' &amp; ', $feed[$x]['title']);
    $description = $feed[$x]['desc'];
    $date = date('l F d, Y, H:m', strtotime($feed[$x]['date']));
    //echo '<p><strong><a " title="'.$title.'">'.$title.'</a></strong><br />';
    //echo '<small><em style="color:red; text-align:center;"> '.$date.'</em>    </small></p>';
//They should be only one echo to trigger success or failure actions in other to play the sound at ajax.
echo "success";
    }
?>