我正在使用curl从网站获取一些数据。处理完后,我设法使其达到此状态:
Array (
[GraphicRiver] => Array ( [0] => stdClass Object
(
[id] => 698515
[item] => Alien Icons Set
[url] => http://graphicriver.net/item/alien-icons-set/698515
[user] => chaoscod3r
[thumbnail] => http://2.s3.envato.com/files/23574322/Thumb.jpg
[sales] => 5
[rating] => 0
[cost] => 5.00
[uploaded_on] => Mon Oct 24 17:16:20 +1100 2011
[tags] => alien icons, clean icons, easy editing, icons pack, minimalist icons pack, resizable, simple icons, vector icons, vector shapes
[category] => icons/miscellaneous
[live_preview_url] => http://3.s3.envato.com/files/23574321/Preview.jpg
)
)
)
但是我想要的是 Array,而不是那个 stdClass 对象,那么我如何重写这种数组来制作那个对象和数组呢?
这是我用来获取上述内容的方法:
public function all_items_by_site($user_name) {
$items_by_marketplace = $this->user_items_by_site($user_name);
$marketplaces = array();
$items = array();
foreach ($items_by_marketplace as $key) {
$marketplaces[] = array(
'Marketplace' => $key->site,
'Items' => $key->items
);
}
foreach ($marketplaces as $key) {
$items[$key['Marketplace']] = $this->new_files_from_user($user_name, $key['Marketplace']);
}
return $items;
}
我正在使用这个 api 包装器作为我想要开发的基本 api 包装器:https://github.com/JeffreyWay/Envato-Marketplace-API-Wrapper-in-PHP .
您可以轻松地将stdClass
对象转换为数组:
$array = (array)$object;
在您的具体案例中,这将是:
foreach ($array['GraphicRiver'] as &$item) {
$item = (array)$item;
}
unset($item);
最简单的方法(尽管这不是真正的语义方式)是使用json_encode
和json_decode
的组合,如下所示:
$array = json_decode(json_encode($orig), true);
这很容易,但我不会为大数组重新评论它。
另一种方法是遍历数组并使用 (array)
应用类型转换:
$array = array_map(function($el) {
return (array)$el;
}, $orig);