使用外键值进行基于角色的访问

我对php和数据库有点陌生。我开发了一个基于角色的访问web应用程序。这个场景是我有两个表

tbl_user

columns -> user_id, username, school_id (school_id是外键)

tbl_school

columns -> school_id, school_name

只有两个角色
管理,用户
用户将基于学校，一旦用户将生成，学校名称将与用户名相关联;user_id

现在我可以显示id，不管是admin还是user

但是一旦用户登录，我希望显示相关的学校名称而不是角色名称。

将非常感谢您的帮助

index . php

        $errors = array(
            1=>"Invalid user name or password, Try again",
            2=>"Please login to access this area"
          );
        $error_id = isset($_GET['err']) ? (int)$_GET['err'] : 0;
        if ($error_id == 1) {
                echo '<p class="text-danger">'.$errors[$error_id].'</p>';
            }elseif ($error_id == 2) {
                echo '<p class="text-danger">'.$errors[$error_id].'</p>';
            }
       ?>
    <form action="authenticate.php" method="post" role="form">
    <div class="form-group">
      <label>UserName :</label>
      <input id="name" name="username" placeholder="username" type="text" class="form-control" required autofocus></div>
      <div class="form-group">
      <label>Password :</label>
      <input id="password" name="password" placeholder="**********" type="password" class="form-control" required></div>
      <input name="submit" type="submit" value=" Login " class="btn btn-primary btn-lg btn-block">
    </form>

AUTHENTICATE.PHP

<?php 
 require 'database-config.php';
 session_start();
 $username = "";
 $password = "";
 if(isset($_POST['username'])){
  $username = $_POST['username'];
 }
 if (isset($_POST['password'])) {
  $password = $_POST['password'];
 } 
 $q = 'SELECT * FROM tbl_user WHERE username=:username AND password=:password';
 $query = $dbh->prepare($q);
 $query->execute(array(':username' => $username, ':password' => $password));
 if($query->rowCount() == 0){
  header('Location: index.php?err=1');
 }else{
  $row = $query->fetch(PDO::FETCH_ASSOC);
  session_regenerate_id();
  $_SESSION['sess_user_id'] = $row['id'];
  $_SESSION['sess_username'] = $row['username'];
        $_SESSION['sess_userrole'] = $row['role'];
        echo $_SESSION['sess_userrole'];
  session_write_close(); 
  $multirole = $row['role'];
    switch ($multirole) {
    case "admin":   
        header('Location: dashboard.php');  
    break;
    case "user":    
        header('Location: user_dashboard.php'); 
    break;
    default:    
    echo "No User Found ! Please Contact Admin";    
    }    
 }? >

DASHBOARD.PHP

<?php 
    session_start();
    $role = $_SESSION['sess_userrole'];
    if(!isset($_SESSION['sess_username']) || $role!="admin"){
      header('Location: index.php?err=2');
    }
? >
html......
Welcome : <?php echo $role; ? >

好吧，这只是一个基于我阅读你的问题的快速建议。

所以你可以问你的问题的数据库…即给我user_id所在的学校名称。您可以这样做(这不是经过测试的代码…)

$q = 'SELECT u.username,s.school_name FROM tbl_user u
JOIN tbl_school s ON u.school_id = s.school_id 
WHERE u.user_id=:user_id';

你只需要给它正确的user_id你就能算出来

这是问，给定user_id(你已经知道了)，给我tbl_school中与user_id的用户表中的school_id相关的学校名称

明白了吗?

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