我正在学习SQL,我的表看起来像这样:
Id Name Payd Note
1 John 5.00 R:8days;U:5$
2 Adam 5.00 R:8days;
3 John 10.00 R:8days;
4 John 10.00 R:8days;
5 Adam 15.00 R:30days;
我想做这样的东西:
Id Name Usage 5.00 10.00 15.00 Sum
1 John 5 5.00 20.00 0 25.00
2 Adam 5.00 0 15.00 20.00
我想检查笔记列中是否有'U:5$',然后向笔记列中有'U:5$'的客户添加5,如果没有,则不添加任何内容。
我的代码是这样的:
;with cte as (
select Customer, PaydAmount, PaydAmount as Payd, Note as Usage
from t1
)
select
Customer, Usage
,[4.00] = ISNULL([4.00],0)
,[5.00] = ISNULL([5.00],0)
,[9.00] = ISNULL([9.00],0)
,[10.00] = ISNULL([10.00],0)
,[15.00] = ISNULL([15.00],0)
,[18.00] = ISNULL([18.00],0)
,[20.00] = ISNULL([20.00],0)
,[25.00] = ISNULL([25.00],0)
,[50.00] = ISNULL([50.00],0)
,[Payd] =ISNULL([4.00],0) + ISNULL([5.00],0) + ISNULL([9.00],0) + ISNULL([10.00],0) + ISNULL([15.00],0) + ISNULL([18.00],0) + ISNULL([20.00],0) + ISNULL([25.00],0) + ISNULL([50.00],0)
from cte
pivot (
sum(PaydAmount) for Payd in ([4.00],[5.00],[9.00], [10.00], [15.00],[18.00], [20.00], [25.00], [50.00]))pvt
order by Customer;
我不确定您的完整输出代表什么。但是使用条件聚合很容易获得前三列:
select row_number() over (order by (select null)) as id,
name,
max(case when note like '%U:5$' then 5 end) as usage,
sum(case when payd = 5.00 then payd else 0 end) as [5.00],
sum(case when payd = 10.00 then payd else 0 end) as [10.00],
sum(case when payd = 15.00 then payd else 0 end) as [15.00],
sum(payd) as total
from cte
group by name;
注意,5、10和15列都假定payd
中的值是十进制/数字类型。不建议对浮点数进行相等比较。