从没有库的字符串中查找子字符串.我知道这很容易，但我找不到我在哪里被这个 if 语句击中

Question

package stringoperation;
import java.util.Scanner;
public class Stringops {
    public static void main(String [] args)
    {
        String string ;
        String sub ; 
        Scanner in = new Scanner(System.in);
        System.out.println("enter a string");
        string =in.nextLine();
        System.out.println("enter a substring to identify");
        sub = in.nextLine();
        char[] array= string.toCharArray(); // converting string to array of char
        char[] subarray  = sub.toCharArray();  //converting sub string to array of char 
        int count=0;
        for(int  j=0;j<array.length;j++)
        {
            if(array[j]==subarray[count]) //till both are same it will run
            {
                if(count==sub.length()-1) //if substring size is reached thats mean matched break out
                {
                    System.out.println("substring is present");
                    break;
                }
                j++;                     
            }
            if(array[j]!=subarray[count]) // otherwise make count as 0 to proceed again 
            {
                count=0;
            }
        }     
    }
}

我检查的if语句仍然找不到错误。我错过了一些东西。只要告诉我我做错了什么。

Answer 1

在确定输入字符串采用预期格式后，尝试使用 string.indexOf(sub) != -1 ;即控制字符(如换行符(不会附加到输入数据中。有必要记住，如果您要比较的字符串不完全匹配，则比较将失败，即

"example" != "Example".