随机随机播放错误消息

Question

嗨，我正在编写一个大富翁游戏模拟器，并有以下列表公益金卡对象内的号码：-

self.CChcards_MessNo = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16]

我想洗牌

这些，用下面的方法

def shuffle(self):
   import random
   random.shuffle(self.CChcards_MessNo)

它在程序的早期工作，但失败并给出以下消息稍后在程序的主要部分。

  File "C:UsersDavidAppDataLocalProgramsPythonPython35librandom.py", line 278, in shuffle
    for i in reversed(range(1, len(x))):
TypeError: object of type 'int' has no len()

当程序循环浏览 16 张牌并且现在需要洗牌时，会发生这种情况

Answer 1

>>> class Foo():
...     def __init__(self):
...         self.CChcards_MessNo = [1,2,3,4,5,6,7,8,9,10,11,12,13,14,15,16]
...     def shuffle(self):
...         import random
...         random.shuffle(self.CChcards_MessNo)
...     def bug(self):
...         print("I'm a bug that makes shuffle() fail by assigning an int to self.CChcards_MessNo")
...         self.CChcards_MessNo = 0
...
>>> foo = Foo()
>>> foo.shuffle()
>>> foo.bug()
I'm a bug that makes shuffle() fail by assigning an int to self.CChcards_MessNo
>>> foo.shuffle()
Traceback (most recent call last):
  File "<stdin>", line 1, in <module>
  File "<stdin>", line 6, in shuffle
  File "C:Program Files (x86)Python36-32librandom.py", line 271, in shuffle
    for i in reversed(range(1, len(x))):
TypeError: object of type 'int' has no len()