C# treeView 有一个代码来安排子节点作为其父节点的最后一个子节点



我正在使用treeView在treeView上显示序列目录及其子目录和文件,我使用以下方法加载树视图

表单加载:

        treeView1.Nodes.Clear();
        toolTip1.ShowAlways = true;
        LoadDirectory("C:\Windows\System32\" + inventedName );  

以及以下3种加载目录和子目录和文件的方法

    public void LoadDirectory(string Dir)
    {
        DirectoryInfo di = new DirectoryInfo(Dir);
        TreeNode tds = treeView1.Nodes.Add(di.Name);
        tds.Tag = di.FullName;
        //tds.StateImageIndex = 0;
        tds.ImageIndex = 0;
        tds.StateImageIndex = 0;
        tds.SelectedImageIndex = 0;
        LoadFiles(Dir, tds);
        LoadSubDirectories(Dir, tds);
    }
    private void LoadSubDirectories(string dir, TreeNode td)
    {
        string[] subdirectoryEntries = Directory.GetDirectories(dir);          
        // Loop through them to see if they have any other subdirectories  
        foreach (string subdirectory in subdirectoryEntries)
        {
            DirectoryInfo di = new DirectoryInfo(subdirectory);
            TreeNode tds = td.Nodes.Add(di.Name);
            renameNodes(tds);    
            //tds.StateImageIndex = 0;
            tds.Tag = di.FullName;
            tds.ImageIndex = 0;
            tds.StateImageIndex = 0;
            tds.SelectedImageIndex = 0;
            LoadFiles(subdirectory, tds);
            LoadSubDirectories(subdirectory, tds);
        }
    }
    private void LoadFiles(string dir, TreeNode td)
    {
        string[] Files = Directory.GetFiles(dir, "*.pdf");
        // Loop through them to see files  
        foreach (string file in Files)
        {
            FileInfo fi = new FileInfo(file);
            TreeNode tds = td.Nodes.Add(fi.Name);
            tds.Tag = fi.FullName;
            tds.ImageIndex = 1;
            tds.StateImageIndex = 1;
            tds.SelectedImageIndex = 1;
        }
    }

我的问题是子目录(文件夹(有特定名称,我无法更改它例如:

> root 
    > parent 
          > 1.0 xxx
          > 1.10 xxx
          > 1.2 xxx
          > 1.3 xxx 
          > 1.4 xxx
          > 1.5 xxx
          > 1.6 xxx
          > 1.7 xxx
          > 1.8 xxx
          > 1.9 xxx

但我需要它像那样

> root 
    > parent 
         > 1.0 xxx
         > 1.2 xxx
         > 1.3 xxx 
         > 1.4 xxx
         > 1.5 xxx
         > 1.6 xxx
         > 1.7 xxx
         > 1.8 xxx
         > 1.9 xxx
         > 1.10 xxx 

愚蠢的 (1.10 XXX( 孩子必须在 (1.9 XXX( 孩子之后正如我所说,我无法重命名错误的文件夹,有什么方法可以将其发送到最后一个孩子

谢谢你帮助我

几周

前我使用IEquable做了一个非常相似的解决方案。 我在下面的代码中对文件名进行了排序以获得正确的解决方案

   public class Test
    {
        private void LoadFiles(string dir, TreeNode td)
        {
            string[] Files = Directory.GetFiles(dir, "*.pdf");
            Files = Files.Select(x => new MySort(x)).OrderBy(x => x).Select(x => x.filename).ToArray();
            // Loop through them to see files  
            foreach (string file in Files)
            {
                FileInfo fi = new FileInfo(file);
                TreeNode tds = td.Nodes.Add(fi.Name);
                tds.Tag = fi.FullName;
                tds.ImageIndex = 1;
                tds.StateImageIndex = 1;
                tds.SelectedImageIndex = 1;
            }
        }
    }
    public class MySort : IComparable
    {
        private string[] splitvalues { get; set; }
        public string filename { get; set; }
        public MySort(string filename)
        {
            this.filename = filename;
            splitvalues = filename.Split(new char[] { '.', ' ' }, StringSplitOptions.RemoveEmptyEntries).ToArray();
        }
        public int CompareTo(object other)
        {
            MySort otherMySort = (MySort)other;
            int min = Math.Min(this.splitvalues.Length, otherMySort.splitvalues.Length);
            for (int i = 0; i < min; i++)
            {
                string a = this.splitvalues[i];
                string b = otherMySort.splitvalues[i];
                if (a != b)
                {
                    int numberA = 0;
                    int numberB = 0;
                    if (int.TryParse(a, out numberA))
                    {
                        if (int.TryParse(b, out numberB))
                        {
                            int z = numberA.CompareTo(numberB);
                            //a & b are numbers
                            return numberA.CompareTo(numberB);
                        }
                        else
                        {
                            //a number b string
                            return -1;
                        }
                    }
                    else
                    {
                        if (int.TryParse(b, out numberB))
                        {
                            //a string b number
                            return 1;
                        }
                        else
                        {
                            // a string b string
                            return a.CompareTo(b);
                        }
                    }
                }
            }
            return splitvalues.Length.CompareTo(otherMySort.splitvalues.Length);
        }
    }

代码工作正常,从下面的测试代码中可以看出。 我做了一个小的更改来添加一个 Sort(( 方法,以便更轻松地调用代码。 其他一切都是一样的。:

using System;
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            string[] input = { "1.7.1", "1.7.10", "1.7.2", "1.7.3", "1.7.4", "1.7.5", "1.7.6", "1.7.7", "1.7.8", "1.7.9" };
            string[] output = MySort.Sort(input);
        }
    }
    public class MySort : IComparable
    {
        private string[] splitvalues { get; set; }
        public string filename { get; set; }
        public MySort(string filename)
        {
            this.filename = filename;
            splitvalues = filename.Split(new char[] { '.', ' ' }, StringSplitOptions.RemoveEmptyEntries).ToArray();
        }
        public static string[] Sort(string[] input)
        {
            return input.Select(x => new MySort(x)).OrderBy(x => x).Select(x => x.filename).ToArray();
        }
        public int CompareTo(object other)
        {
            MySort otherMySort = (MySort)other;
            int min = Math.Min(this.splitvalues.Length, otherMySort.splitvalues.Length);
            for (int i = 0; i < min; i++)
            {
                string a = this.splitvalues[i];
                string b = otherMySort.splitvalues[i];
                if (a != b)
                {
                    int numberA = 0;
                    int numberB = 0;
                    if (int.TryParse(a, out numberA))
                    {
                        if (int.TryParse(b, out numberB))
                        {
                            int z = numberA.CompareTo(numberB);
                            //a & b are numbers
                            return numberA.CompareTo(numberB);
                        }
                        else
                        {
                            //a number b string
                            return -1;
                        }
                    }
                    else
                    {
                        if (int.TryParse(b, out numberB))
                        {
                            //a string b number
                            return 1;
                        }
                        else
                        {
                            // a string b string
                            return a.CompareTo(b);
                        }
                    }
                }
            }
            return splitvalues.Length.CompareTo(otherMySort.splitvalues.Length);
        }
    }
}

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