使用C#serial.write拉动任意Arduino引脚

Question

我正在用C#编写一个应用程序，它将向我的COM端口发送一个serial.write。我看到的所有C#控制Arduino引脚的例子都集中在只拉一个引脚上。下面是我的代码。我现在只能把引脚9拉到HIGH，其他读取命令都不起作用。男生的错误在哪里？：(

Arduino代码：

void setup() {
// Define inputs and outputs
pinMode(0, INPUT);
pinMode(1, INPUT);
pinMode(2, INPUT);
pinMode(3, INPUT);
pinMode(4, INPUT);
pinMode(5, INPUT);
pinMode(6, INPUT);
pinMode(7, INPUT);
pinMode(8, INPUT);
pinMode(9, OUTPUT);
pinMode(10, OUTPUT);
pinMode(11, OUTPUT);
pinMode(12, OUTPUT);
// Begin Serial communication at a baudrate of 9600:
Serial.begin(9600);
}
void loop() {
if (Serial.read() == 'a')
{
digitalWrite(9, HIGH);
}
else if (Serial.read() == 'b')
{
digitalWrite(9, LOW);
}

else if (Serial.read() == 'c')
{
digitalWrite(10, HIGH);
}
else if (Serial.read() == 'd')
{
digitalWrite(10, LOW);
}
else if (Serial.read() == 'e')
{
digitalWrite(11, HIGH);
}
else if (Serial.read() == 'f')
{
digitalWrite(11, LOW);
}
else if (Serial.read() == 'g')
{
digitalWrite(12, HIGH);
}
else if (Serial.read() == 'h')
{
digitalWrite(12, LOW);
}
delay(100);

}

C#代码

private void btnOP9on_Click(object sender, EventArgs e)
{
serialPort1.Write("a");
}
private void btnOP9off_Click(object sender, EventArgs e)
{
serialPort1.Write("b");
}

Answer 1

从序列中读取一个字符会消耗它。您不能再读取同一个字符。你需要阅读一次连载，然后将其与所有不同的东西进行比较。

void loop() {
char c = 0;
if(Serial.available()){
c = Serial.read();
}
if (c == 'a')
{
digitalWrite(9, HIGH);
}
else if (c == 'b')
{
digitalWrite(9, LOW);
}

else if (c == 'c')
{
digitalWrite(10, HIGH);
}
else if (c == 'd')
{
digitalWrite(10, LOW);
}
else if (c == 'e')
{
digitalWrite(11, HIGH);
}
else if (c == 'f')
{
digitalWrite(11, LOW);
}
else if (c == 'g')
{
digitalWrite(12, HIGH);
}
else if (c == 'h')
{
digitalWrite(12, LOW);
}
delay(100);

}