内部模式可变

Question

var seperator = ',', group = 'red, blue';
//group.search(seperator/g) - g is not defined
group.search(/seperator/g) // looks for "seperator"
group.search('/' + seperator + '/g') // doesn't seem to find my "seperator"

说到这里，我已经没有主意了……如何在表达式内得到seperator ?

提前感谢!

Answer 1

您需要创建新的regexp对象

var test = new RegExp(seperator, 'g');
group.search(test)