Python，Fizz Buzz插入范围作为函数的参数

Question

我正在使用嘶嘶声练习来学习一些关于python的知识。我已经硬编码了 1-100 的范围，但我很好奇如何使用参数将范围传递到函数中来实现相同的结果？

numbers = range (1,101)
def fizzbuzz(numbers):
    for each in numbers:
        if each % 3 == 0 and each % 5 == 0:
            print "fizzbuzz"
        elif each % 3 == 0:
            print "fizz"
        elif each % 5 == 0:
            print "buzz"
        else:
            print each
print fizzbuzz(numbers)

Answer 1

你可以使用 Python 的 itertools.count 并只传入最大值。

https://docs.python.org/2/library/itertools.html

def fizzbuzz(num):
    for i in itertools.count(start=1,step=1):
        if (i==num):
            break
        ..fizzbuz logic
fizzbuzz(num)

Answer 2

def fizzbuzz(num_range):
    for each in num_range:
        if each % 3 == 0 and each % 5 == 0:
            print "fizzbuzz"
        elif each % 3 == 0:
            print "fizz"
        elif each % 5 == 0:
            print "buzz"
        else:
            print each
print fizzbuzz(range (1,101))