查找会员(患者)数量最多的保险公司。
这就是数据库,也是我第一次尝试接近:
http://sqlfiddle.com/#!3/4b2ed/27
SELECT P.cid AS cid, COUNT ( P.pid ) AS CountP
FROM Patient P
GROUP BY P.cid
如何获得最大计数?
只需按患者数量降序排列结果,仅取第一条记录。
SELECT P.cid AS cid, COUNT( P.pid ) AS CountP
FROM Patient P
GROUP BY P.cid
ORDER BY CountP DESC
LIMIT 1
如果多个保险公司可能拥有最大数量的成员,并且您希望获取所有成员,则需要使用子查询:
SELECT P.cid AS cid, COUNT( P.pid ) AS CountP
FROM Patient P
GROUP BY P.cid
HAVING CountP = (
SELECT COUNT(pid) AS c
FROM Patient
GROUP BY cid
ORDER BY c DESC
LIMIT 1
);
在您在评论中描述的奇怪情况下,无法使用LIMIT
,您可以执行以下操作:
SELECT P.cid AS cid, COUNT( P.pid ) AS CountP
FROM Patient P
GROUP BY P.cid
HAVING CountP = (SELECT MAX(d.c) FROM (
SELECT COUNT(pid) AS c
FROM Patient
GROUP BY cid
) AS d);
尝试以下操作:
最大(计数(P.pid))
SELECT P.cid, COUNT ( P.pid ) AS CountP
FROM Patient P
GROUP BY P.cid
compute max(count(p.pid))
哇 - 很多约束。 给你:
SELECT MAX(CountP) FROM (
SELECT P.cid, COUNT ( P.pid ) AS CountP
FROM Patient P
GROUP BY P.cid
) winner