我正在尝试从用户那里获取字符串输入并将其存储在文件中,但出现错误说:我不知道问题是什么,直到我实际运行代码,它才会弹出为错误。我只想将用户的输入存储在制作的文件中
Exception in thread "main" java.lang.NullPointerException
at BingoHelper.<init>(BingoHelper.java:53)
at BINGO.main(BINGO.java:8)
主类代码:
import javax.swing.*;
import java.io.*;
public class BINGO {
public static void main(String[] args) throws IOException{
JLabel bg = new JLabel();
//JButton b = new JButton("Click to enter name");
BingoHelper EnterFaze = new BingoHelper();
EnterFaze.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE);
EnterFaze.setSize(500,500);
EnterFaze.setVisible(true);
EnterFaze.setLocationRelativeTo(null);
EnterFaze.setLayout(null);
EnterFaze.add(bg);
}
}
二等舱
import javax.swing.*;
import java.awt.*;
import java.awt.event.*;
import java.io.*;
public class BingoHelper extends JFrame implements WindowListener, ActionListener{
JTextField text = new JTextField();
JLabel bg = new JLabel();
private JButton b; {
b = new JButton("Click to enter name");
}
JPanel pnlButton = new JPanel();
public static String fn;
public static String sn;
public void actionPerformed (ActionEvent e) {
//BingoHelper.fn;
//BingoHelper.sn;
fn = JOptionPane.showInputDialog("What is your first name?");
sn = JOptionPane.showInputDialog("What is your second name(Optional)");
//JOptionPane.showMessageDialog(null, "Welcome " + fn + " " + sn + ".", "", JOptionPane.INFORMATION_MESSAGE);
text.setText("Welcome " + fn + " " + sn + ".");
b.setVisible(false);
text.setVisible(true);
text.setBounds(140,0,220,20);
text.setHorizontalAlignment(JLabel.CENTER);
text.setEditable(false);
text.setBackground(Color.YELLOW);
}
public BingoHelper() throws IOException{
super("BINGO");
add(text);
text.setVisible(false);
add(b);
this.add(pnlButton);
pnlButton.setBackground(Color.BLUE);
//pnlButton.add(b);+
b.setVisible(true);
b.setBounds(145,145,145,20);
//b.setPreferredSize(new Dimension(150,40));
b.addActionListener(this);
b.setBackground(Color.GREEN);
rootPane.setDefaultButton(b);
File f = new File("test.txt");
String nameToWrite = fn;
OutputStream outStream = new FileOutputStream(f);
outStream.write(nameToWrite.getBytes());
outStream.close();
}
public void windowClosing(WindowEvent e) {
dispose();
System.exit(0);
}
public void windowOpened(WindowEvent e) {}
public void windowActivated(WindowEvent e) {}
public void windowIconified(WindowEvent e) {}
public void windowDeiconified(WindowEvent e) {}
public void windowDeactivated(WindowEvent e) {}
public void windowClosed(WindowEvent e) {}
}
这是问题所在:
String nameToWrite = fn;
...
outStream.write(nameToWrite.getBytes());
fn
只有在至少调用actionPerformed
一次后才会具有非 null 值。因此,当您调用构造函数时,fn
为 null,因此 nameToWrite
为 null,因此nameToWrite.getBytes()
抛出NullPointerException
。此时你期望得到什么名字?为什么要在构造函数期间写入文件?这似乎是一件非常奇怪的事情。它不应该是为了响应用户操作而编写的吗?
(顺便说一句,无论如何,不要在没有指定字符集的情况下使用 getBytes()
- 并且更喜欢围绕OutputStream
创建OutputStreamWriter
,而不是自己执行文本到二进制的转换。并使用 finally 块或资源尝试语句关闭流。
将帮助程序代码更改为以下内容以获取所需的内容。 我所做的改变是,
- 删除了要在构造函数中写入文件的代码。
- 添加了写入文件的新方法。
- 已从操作执行调用新方法。
public class BingoHelper extends JFrame implements WindowListener, ActionListener {
JTextField text = new JTextField();
JLabel bg = new JLabel();
private JButton b;
{
b = new JButton("Click to enter name");
}
JPanel pnlButton = new JPanel();
public static String fn;
public static String sn;
public void actionPerformed(ActionEvent e) {
// BingoHelper.fn;
// BingoHelper.sn;
fn = JOptionPane.showInputDialog("What is your first name?");
sn = JOptionPane.showInputDialog("What is your second name(Optional)");
// JOptionPane.showMessageDialog(null, "Welcome " + fn + " " + sn + ".", "",
// JOptionPane.INFORMATION_MESSAGE);
text.setText("Welcome " + fn + " " + sn + ".");
b.setVisible(false);
text.setVisible(true);
text.setBounds(140, 0, 220, 20);
text.setHorizontalAlignment(JLabel.CENTER);
text.setEditable(false);
text.setBackground(Color.YELLOW);
writeToFile();
}
private void writeToFile() {
File f = new File("test.txt");
String nameToWrite = fn;
OutputStream outStream = null;
try {
outStream = new FileOutputStream(f);
outStream.write(nameToWrite.getBytes());
} catch (IOException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} finally {
if (null != outStream) {
try {
outStream.close();
} catch (IOException e) {
// do nothing
}
}
}
}
public BingoHelper() throws IOException {
super("BINGO");
add(text);
text.setVisible(false);
add(b);
this.add(pnlButton);
pnlButton.setBackground(Color.BLUE);
// pnlButton.add(b);+
b.setVisible(true);
b.setBounds(145, 145, 145, 20);
// b.setPreferredSize(new Dimension(150,40));
b.addActionListener(this);
b.setBackground(Color.GREEN);
rootPane.setDefaultButton(b);
}
public void windowClosing(WindowEvent e) {
dispose();
System.exit(0);
}
public void windowOpened(WindowEvent e) {
}
public void windowActivated(WindowEvent e) {
}
public void windowIconified(WindowEvent e) {
}
public void windowDeiconified(WindowEvent e) {
}
public void windowDeactivated(WindowEvent e) {
}
public void windowClosed(WindowEvent e) {
}}
你得到了一个 NullPointerException,因为 fn 是空的。NullPointerException在Java编程中非常常见,你应该在引发异常的行号中查看所有变量。为了更好地理解NullPointerException,请参阅 http://javapapers.com/core-java/nullpointerexception-null-bad-good-and-ugly/
你真的要从构造函数写入文件吗?