有意启动新详细信息活动时传递的内容错误

Question

我正在通过ListViewItem的intent启动一个新的"活动"。但是，new detail Activity在-1位置显示ListViewItem的信息。

我在这里实例化并启动活动：

ListView list = (ListView)findViewById(R.id.merchListView);
list.setAdapter(merchItemArrayAdapter);
list.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        Toast.makeText(getApplication(),String.format("view==>%s, position ==> %s, id==> %s",view.toString(),position,id),Toast.LENGTH_SHORT).show();
        System.out.println(String.format("view==>%s, position ==> %s, id==> %s",view.toString(),position,id));
        //Build Intent
        Intent intent = new Intent(getApplicationContext(),MerchItemDescription.class);

        TextView tv1 = (TextView) findViewById(R.id.textView2);
        TextView tv2 = (TextView) findViewById(R.id.costView);
        ImageView iv1 = (ImageView) findViewById(R.id.imageView);

        System.out.println(String.format("Imageview id is ==> %d",R.id.imageView));
        iv1.buildDrawingCache();
        Bitmap imageViewImage = iv1.getDrawingCache();
        Bundle extras = new Bundle();
        extras.putParcelable("imagebitmap", imageViewImage);
        //extras.putParcelable("theView", view);
        intent.putExtras(extras);
        String message = tv1.getText().toString();
        intent.putExtra(EXTRA_MESSAGE, message);

        String costViewString = tv2.getText().toString();
        intent.putExtra(ITEM_COST,costViewString);


        startActivity(intent);
    }
});

这是传递给Intent的类：

setContentView(R.layout.merch_item_description);
        Intent intent = getIntent();
        String message = intent.getStringExtra(MainActivityTest.EXTRA_MESSAGE);

        System.out.println(String.format("Message ==> %s", message));
        //View merchDescView = getLayoutInflater().inflate(R.layout.merch_item_description, null, false);

        Bundle extras = getIntent().getExtras();
        Bitmap bmp = (Bitmap) extras.getParcelable("imagebitmap");
        //View myView = (View) extras.getParcelable("theView");
        TextView txtView2 = (TextView)findViewById(R.id.textViewLongDesc);
        //TextView txtView2 = (TextView) myView.findViewById(R.id.textViewLongDesc);
        txtView2.setText(message);

        ImageView iv = (ImageView)findViewById(R.id.itemDescIV);
        //ImageView iv = (ImageView) myView.findViewById(R.id.itemDescIV);

        iv.setImageBitmap(bmp);

Answer 1

如果tv1、tv2和iv1是ListView中项目的子级，而不是：

TextView tv1 = (TextView) findViewById(R.id.textView2);
TextView tv2 = (TextView) findViewById(R.id.costView);
ImageView iv1 = (ImageView) findViewById(R.id.imageView);

你的意思可能是：

TextView tv1 = (TextView) view.findViewById(R.id.textView2);
TextView tv2 = (TextView) view.findViewById(R.id.costView);
ImageView iv1 = (ImageView) view.findViewById(R.id.imageView);

它可能在"活动"中查找第一个R.id*，而不是子视图。