如何解开ipython中的shell逃生的输出?
示例(工作):
In [1]: !locate .hgrc
/home/wim/.hgrc
/usr/share/doc/mercurial-common/examples/sample.hgrc
In [2]: hgrcs = !locate .hgrc
In [3]: hgrcs[0]
Out[3]: '/home/wim/.hgrc'
但这不起作用:
In [4]: hgrc0, *rest = !locate .hgrc
File "<ipython-input-4-e8900264b4a8>", line 1
hgrc0, *rest = !locate .hgrc
^
SyntaxError: invalid syntax
也不起作用:
In [13]: x = !locate .hgrc | head -1
In [14]: x
Out[14]: ['/home/wim/.hgrc']
In [15]: x, = !locate .hgrc | head -1
File "<ipython-input-15-524d2c9ab16f>", line 1
x, = !locate .hgrc | head -1
^
SyntaxError: invalid syntax
ipython 0.13.2在Python 3.3.2 上。
icky,但对于这种特殊情况:
hgrc0, _ = !locate .hgrc | head -1 | printf '%sn_' $(cat)
我提交问题后不久就解决了。
https://github.com/ipython/ipython/pull/5321