我正试图从InputStream读取数据,这可能是FileInputStream或ObjectInputStream。为了实现这一点,我想克隆流并尝试读取对象,并在出现异常的情况下使用apache commons io将流转换为字符串。
PipedInputStream in = new PipedInputStream();
TeeInputStream tee = new TeeInputStream(stream, new PipedOutputStream(in));
Object body;
try {
ObjectInput ois = new ObjectInputStream(tee);
body = ois.readObject();
} catch (Exception e) {
try {
body = IOUtils.toString(in, Charset.forName("UTF-8"));
} catch (Exception e2) {
throw new MarshallerException("Could not convert inputStream");
}
}
不幸的是,这不起作用,因为程序在尝试将流in
转换为字符串时等待传入数据。
正如Boris Spider已经评论的那样,可以读取整个流,例如到字节数组流,然后在该资源上打开新的流:
byte[] byteArray = IOUtils.toByteArray(stream);
InputStream input1 = new ByteArrayInputStream(byteArray);
InputStream input2 = new ByteArrayInputStream(byteArray);
Object body;
try {
ObjectInput ois = new ObjectInputStream(input1);
body = ois.readObject();
} catch (Exception e) {
try {
body = IOUtils.toString(input2, Charset.forName("UTF-8"));
} catch (Exception e2) {
throw new MarshalException("Could not convert inputStream");
}
}