Django-，在模型表单中显示和过滤外键中的特定字段

Question

我正在使用模型表单，该字段是外键，对于另一个模型，外键模型包含一个选择字段(状态(，我希望根据用户组进行过滤，这样如果用户属于一个组，例如如果用户在组中 DEVELOPER，可用的状态选项将是"每周任务"和"每日任务">

models.py

class ScrumyGoals(models.Model):
user_name=models.ForeignKey('ScrumyUser', on_delete= models.CASCADE, null= True)
status_id = models.ForeignKey('GoalStatus', on_delete=models.CASCADE,null=True)
goal_type = models.CharField(choices=GOAL_TYPE, max_length=64, default='DT')
def __str__(self):
return '{},{}'.format(self.user_name,self.status_id)
class GoalStatus(models.Model):
GOALS_TYPE= (('DT','Daily Task'),
('WT','Weekly Task'),
('V','Verified'),
('D','Done'),
)
title = models.CharField(max_length=254, null=True) 
task_id=models.IntegerField(default=1,null=False)
description =models.CharField(max_length=254)
verified_by=models.ForeignKey('ScrumyUser', on_delete= models.CASCADE, null=True)
status=models.CharField(choices=GOALS_TYPE, max_length=2, default='DT')

forms.py

class ChangeTaskForm(forms.ModelForm):
class Meta:
model = ScrumyGoals
fields = ['status_id']
def __init__(self, *args, **kwargs):
user = kwargs.pop('user', None)
super(ChangeTaskForm, self).__init__(*args, **kwargs)
if user.groups.filter(name ='DEVELOPER').exists():
self.fields['status'].choices = (('WT','Weekly Task'), ('DT','Daily Task'),)

views.py

def changetask(request):
if request.method == 'POST':
form = ChangeTaskForm(request.POST, user=request.user)
if form.is_valid():
return HttpResponseRedirect('/index/')
else:
form = ChangeTaskForm(user=request.user)
return render(request, 'oderascrumy/changetask.html', {'form': form})

表单目前仅显示status_id，不显示选项(即"状态"(

所以本质上我想要的是，如果登录用户在组中说"DEVELOPER"，用户只能将目标(即"status_id"(选择(即"状态"(从每周任务更改为每日任务并保存表单

Answer 1

如果您从 forms.py 中删除if，即您是否确定名为"DEVELOPER"的组存在，并且您正在测试的用户实际上在该组中？

另一种方法是始终在fields中包含status，然后有条件地在模板中显示该字段并带有if user.groups in ['DEVELOPER']。