我发出请求并等待响应流上对该请求的响应。在等待期间,更新流上可能会有更新。
我希望在回复流完成后进行这些更新。喜欢这个:
Response (cold) | x y z |
Updates (hot) | 1 2 3 4 |
Result | x y z 123 4 |
我似乎做不好。是否有一些聪明的运算符组合可以满足我的需求?
从问题的图表中:
缓冲所有更新,直到响应完成,然后按显示的其余更新显示。响应会立即显示。
updates.TakeUntil(response.LastAsync())
.ToArray()
.SelectMany(x => x)
.Concat(updates)
.Merge(response);
这将起作用,尽管你不能作为单行代码做到这一点的事实困扰着我:
var updatesReplayed = updates.Replay();
updatesReplayed.Connect();
var results = response.Concat(updatesReplayed);
以下是演示该功能的测试:
// time | 1 2 3 4 5 6 7 8 9
// Response(cold) | x y z |
// Updates(hot) | 1 2 3 4 |
// Result | x y z 123 4 |
var scheduler = new TestScheduler();
var updates = scheduler.CreateHotObservable(
ReactiveTest.OnNext(100.ToMsTicks(), "1"),
ReactiveTest.OnNext(200.ToMsTicks(), "2"),
ReactiveTest.OnNext(400.ToMsTicks(), "3"),
ReactiveTest.OnNext(800.ToMsTicks(), "4"),
ReactiveTest.OnCompleted<string>(900.ToMsTicks())
);
var response = scheduler.CreateColdObservable(
ReactiveTest.OnNext(300.ToMsTicks(), "x"),
ReactiveTest.OnNext(400.ToMsTicks(), "y"),
ReactiveTest.OnNext(500.ToMsTicks(), "z"),
ReactiveTest.OnCompleted<string>(600.ToMsTicks())
);
var expectedResults = scheduler.CreateHotObservable(
ReactiveTest.OnNext(300.ToMsTicks(), "x"),
ReactiveTest.OnNext(400.ToMsTicks(), "y"),
ReactiveTest.OnNext(500.ToMsTicks(), "z"),
ReactiveTest.OnNext(600.ToMsTicks(), "1"),
ReactiveTest.OnNext(600.ToMsTicks(), "2"),
ReactiveTest.OnNext(600.ToMsTicks(), "3"),
ReactiveTest.OnNext(800.ToMsTicks(), "4"),
ReactiveTest.OnCompleted<string>(900.ToMsTicks())
);
var replayed = updates.Replay();
replayed.Connect();
var results = response.Concat(replayed);
var observer = scheduler.CreateObserver<string>();
results.Subscribe(observer);
scheduler.Start();
ReactiveAssert.AreElementsEqual(expectedResults.Messages, observer.Messages);