当我从最后一个片段返回时，如何避免活动的空白屏幕

Question

在这里我正在使用

public void replaceFragment(Fragment fragment, boolean isMainPage, Bundle bundle) {
String backStateName = fragment.getClass().getName();
FragmentManager manager = getSupportFragmentManager();
boolean fragmentPopped = manager.popBackStackImmediate(backStateName, 0);
if (bundle != null) {
fragment.setArguments(bundle);
}
System.out.println("isMainPage :: " + isMainPage);
System.out.println("FRAGMENT NAME :: " + backStateName + " fragmentPopped :: " + fragmentPopped);
if (!fragmentPopped) { //fragment not in back stack, create it.
FragmentTransaction transaction = manager.beginTransaction();
transaction.replace(R.id.main_fragment, fragment);
if (isMainPage) {
getSupportFragmentManager().popBackStack(null, FragmentManager.POP_BACK_STACK_INCLUSIVE);
}
int backStackCount = getSupportFragmentManager().getBackStackEntryCount();
System.out.println("backStackCount :: " + backStackCount);
transaction.addToBackStack(backStateName);
transaction.commit();
}
}

用于替换整个项目中的片段。我的问题是，当我从最后一个片段弹出时，它会显示空白页，我的框架布局放置在其中以替换片段

<FrameLayout
android:id="@+id/main_fragment"
android:layout_width="match_parent"
android:layout_height="match_parent"/>

Answer 1

只需从代码中删除此行，它就会解决您的问题。

transaction.addToBackStack(backStateName);

解释

您在堆栈中添加了片段，以便在首先返回时，片段从后退堆栈中弹出，并且空容器可见。

注意：如果要为片段指定标签名称，只需将这一行代码transaction.replace(R.id.main_fragment, fragment);替换为此transaction.replace(R.id.main_fragment, fragment, backStateName);