我有一些格式如下或略有不同的 xml 文件
<?xml version="1.0"?>
<!DOCTYPE PARTS SYSTEM "parts.dtd">
<?xml-stylesheet type="text/css" href="xmlpartsstyle.css"?>
<PARTS>
<TITLE>Computer Parts</TITLE>
<ASST>
<PART no="xs@@">
<ITEM>Motherboard</ITEM>
<MANUFACTURER>ASUS</MANUFACTURER>
<MODEL ver="v-@@@@">P3B-F</MODEL>
<COST>123.00</COST>
</PART>
<PART no="xs@@">
<ITEM>Video Card</ITEM>
<MANUFACTURER>ATI</MANUFACTURER>
<MODEL ver="v-@@@@">All-in-Wonder Pro</MODEL>
<COST>160.00</COST>
</PART>
<PART no="xs@@">
<ITEM>Sound Card</ITEM>
<MANUFACTURER>Creative Labs</MANUFACTURER>
<MODEL ver="v-@@@@">Sound Blaster Live</MODEL>
<COST>80.00</COST>
</PART>
</ASST>
</PARTS>
我正在尝试以顺序方式生成节点 <PART>
的属性值,即 no 和 <MODEL>
即 ver,从值 1 开始,然后从下一个<PART>
节点递增 +1。所以,基本上所需的输出应该看起来像这样
<?xml version="1.0"?>
<!DOCTYPE PARTS SYSTEM "parts.dtd">
<?xml-stylesheet type="text/css" href="xmlpartsstyle.css"?>
<PARTS>
<TITLE>Computer Parts</TITLE>
<ASST>
<PART no="xs1">
<ITEM>Motherboard</ITEM>
<MANUFACTURER>ASUS</MANUFACTURER>
<MODEL ver="v-1">P3B-F</MODEL>
<COST>123.00</COST>
</PART>
<PART no="xs2">
<ITEM>Video Card</ITEM>
<MANUFACTURER>ATI</MANUFACTURER>
<MODEL ver="v-2">All-in-Wonder Pro</MODEL>
<COST>160.00</COST>
</PART>
<PART no="xs3">
<ITEM>Sound Card</ITEM>
<MANUFACTURER>Creative Labs</MANUFACTURER>
<MODEL ver="v-3">Sound Blaster Live</MODEL>
<COST>80.00</COST>
</PART>
</ASST>
</PARTS>
那么,使用 LINQ to-XML 执行此操作的最简单方法是什么?
我试图像
string filecontent=File.ReadAllText(@"C:UsersDesktop12-apr.xml");
XDocument xml=XDocument.Parse(filecontent);
var parts=xml.Descendants("PART");
var models=xml.Descendants("PART").Elements("MODEL");
foreach (var part in parts)
{
for (int i = 0; i < parts.Count(); i++)
{
part.Attribute("no").Value="xs"+i.ToString();
}
}
foreach (var model in models)
{
for (int i = 0; i < parts.Count(); i++)
{
model.Attribute("ver").Value="v-"+i.ToString();
}
}
xml.Save(@"C:UsersDesktop12-apr.xml");
Console.ReadLine();
但它没有按照我想要的方式工作。我的代码生成的输出
<?xml version="1.0" encoding="utf-8"?>
<!DOCTYPE PARTS SYSTEM "parts.dtd"[]>
<?xml-stylesheet type="text/css" href="xmlpartsstyle.css"?>
<PARTS>
<TITLE>Computer Parts</TITLE>
<ASST>
<PART no="xs2">
<ITEM>Motherboard</ITEM>
<MANUFACTURER>ASUS</MANUFACTURER>
<MODEL ver="v-2">P3B-F</MODEL>
<COST>123.00</COST>
</PART>
<PART no="xs2">
<ITEM>Video Card</ITEM>
<MANUFACTURER>ATI</MANUFACTURER>
<MODEL ver="v-2">All-in-Wonder Pro</MODEL>
<COST>160.00</COST>
</PART>
<PART no="xs2">
<ITEM>Sound Card</ITEM>
<MANUFACTURER>Creative Labs</MANUFACTURER>
<MODEL ver="v-2">Sound Blaster Live</MODEL>
<COST>80.00</COST>
</PART>
</ASST>
</PARTS>
帮助
你无缘无故地嵌套了循环......您为每个元素多次设置属性,而不是为每个元素设置一次属性。
一旦你摆脱了嵌套循环,它就很简单了。不过,如果您将查询具体化为列表,则更简单。下面是生成所需输出的完整示例:
using System;
using System.Linq;
using System.Xml.Linq;
class Test
{
static void Main()
{
var xml = XDocument.Load("input.xml");
var parts = xml.Descendants("PART").ToList();
var models = xml.Descendants("PART").Elements("MODEL").ToList();
for (int i = 0; i < parts.Count; i++)
{
parts[i].Attribute("no").Value = $"xs{i+1}";
}
for (int i = 0; i < models.Count; i++)
{
models[i].Attribute("ver").Value = $"v-{i+1}";
}
xml.Save("output.xml");
}
}