快速移动范围占2个或排除找到的字符

Question

这可能是一个基本问题，但是我很难不包括 - 第二个

var title1 = "I will be part of string 1 - I am part of string 2"
let end = title1.range(of: "-", options: .backwards)?.lowerBound
let firstPartRange = title1.startIndex..<end!
var secondPart = title1.substring(with: firstPartRange) // Gives me "I will be part of string 1" which is correct 
title1.substring(from: end!) // however this guy gives me "- I am part of string 2" & I only want to get "I am part of string 2" without the space and dash in front

我可以以某种方式改变范围或更改其下部？我知道我可以在此处通过函数用用户将组件用户分开，但是想学习如何抵消我的范围

Answer 1

您只需要在结束后获得索引或将其取代。请注意，您还应确保使用方法index(theIndex, offsetBy: n, limitedBy: endIndex)

确保它不会通过结束索引。

let title1 = "I will be part of string 1 - I am part of string 2"
if let end = title1.range(of: "-", options: .backwards)?.lowerBound {
    let firstPartRange = title1.startIndex..<end
    let secondPart = title1.substring(with: firstPartRange)  // "I will be part of string 1 "
    title1.substring(from: title1.index(after: end))         // " I am part of string 2"
    // or to offset it by two you should also make sure it doesn't pass the end index 
    title1.substring(from: title1.index(end, offsetBy: 2, limitedBy: title1.endIndex) ?? title1.endIndex)   // "I am part of string 2"
}

Answer 2

您正在寻找index(_:offsetBy:)。这是原始字符串的方法，例如：

var title1 = "I will be part of string 1 - I am part of string 2"
let end = title1.range(of: "-", options: .backwards)!.lowerBound
let ix = title1.index(end, offsetBy: 2)
title1.substring(from: ix) // "I am part of string 2"

Answer 3

您可以使用组件(分隔：字符串(方法将字符串的内容分开最后一个元素。

var title1 = "I will be part of string 1 - I am part of string 2"
print(title1.components(separatedBy: "-").last!.trimmingCharacters(in: .whitespacesAndNewlines))

它将为您提供所需的结果

"我是字符串2"

的一部分

希望它有帮助！

Answer 4

您可以使用组件函数，并在分隔器中包含空格：

title1.components(separatedBy:" - ")

Answer 5

@matt建议，您正在寻找 index(_:offsetBy:)

仅使用SWIFT标准库(无基础(

有点不同的方法

let str = "I will be part of string 1 - I am part of string 2"
let parts = str.characters.split(separator: "-").map(String.init)

如果您想修剪所有额外的空间

let partsTrimmed = parts.map {
    $0.characters.split(separator: " ").map(String.init).joined(separator: " ")
}