如何在行为/python中传递参数

Question

我想知道如何传递真或假参数。(config_type = True( 使用 Python 语言中的行为。

Scenario Outline:
Given 
upload xls with parameters "shop" xlsx (path: "./upload12.xlsx") definition named "config_short" and  "<config_type>"
Examples:
| config_type|
| False    |
@given('upload xls with parameters "sh" xlsx (path: "./upload12.xlsx") definition named "config_short" and  "{config_type}"')
def step_impl(context, config_type)
definition = someMethod(xlsx_path, config_short, config_type=True)

这是在BDD中传递此类参数的正确方法吗？在下一个测试中，我想重用该someMethod但要config_type = False

Answer 1

我认为你很接近，但需要将config_type参数传递给某个方法：

Scenario Outline:
Given upload xls with parameters "shop" xlsx (path: "./upload12.xlsx") definition named "config_short" and  "<config_type>"
Examples:
| config_type|
| False    |
@given('upload xls with parameters "sh" xlsx (path: "./upload12.xlsx") definition named "config_short" and  "{config_type}"')
def step_impl(context, config_type):
definition = someMethod(xlsx_path, config_short, config_type=config_type)

也就是说，你可以用这样的东西来清理它：

功能文件：

Scenario Outline:
Given upload xls with parameters "<type>" xlsx (path: "<xls_path>") definition named "<config_name>" and  "<config_type>"
Examples:
| type | xls_path        | config_name  | config_type|
| shop | ./upload12.xlsx | config_short | False    |

步骤文件：

@given('upload xls with parameters "{type}" xlsx (path: "{xls_path}") definition named "{config_name}" and  "{config_type}"')
def step_impl(context, type, xls_path, config_name, config_type):
definition = someMethod(xlsx_path=xls_path, config_short=config_short, config_type=config_type)