将Javascript三元函数转换为简单函数

Question

我有一个三元函数

const resetCompletion = completed < 0 ? 0 : completed > 100 ? 100 : completed;

我需要将它转换为if else if else块的一个简单函数。什么应该是正确的方式？

Answer 1

下面的代码片段可能相当于if块的三元运算。

const resetCompletion = completed => {
if (completed < 0) {
return 0;
}
if (completed > 100) {
return 100;
}
return completed;
};
let completed = 101;
console.log(resetCompletion(completed));
completed = -100;
console.log(resetCompletion(completed));
completed = 10;
console.log(resetCompletion(completed));

Answer 2

它可以扩展到类似的东西：

let resetCompletion = completed;
if (completed < 0) { resetCompletion = 0; }
else if (completed > 100) { resetCompletion = 100; }

这意味着"；默认情况下，resetCompletion等于completion。然而，如果completed小于零，那么resetCompletion等于零，否则如果completed大于100，则resetCompletion等于100〃