我在C#中遇到了一个反射问题。我需要构造一个通用方法,用反射动态实例化类类型。我尝试的是以下内容。
Type myClass = Type.GetType(deviceBehavior.@class);
Type myInterfaceClass = myClass.GetInterface(deviceBehavior.@interface);
if (typeof (AnotherInterface).IsAssignableFrom(interfaceClass))
{
CreateManager<interfaceClass>(serviceProvider, deviceCapability);
}
我的CreateManager方法如下:
private void CreateManager<T>(ServiceProvider serviceProvider, DeviceCapability deviceCapability)
{
T instanceToCreate = CreateClass<T>(serviceProvider, deviceCapability);
//Code to instantiate my class
}
问题是我打不到
CreateManager(serviceProvider,deviceCapability);
如何将接口传递给泛型类型?我搜索了一下,找不到任何我能清楚理解的东西。即
对泛型类型参数调用静态方法
传递实例化的System.Type作为泛型类的类型参数
假设CreateManager<T>
是类型为Foo
:的方法
public class Foo
{
private void CreateManager<T>(ServiceProvider serviceProvider,
DeviceCapability deviceCapability)
{
}
}
为了动态调用泛型方法,您需要首先获得MethodInfo
,然后使用要传递的实际类型调用MakeGenericMethod
(我选择string
作为示例)
var foo = new Foo();
var createManagerMethod = foo.GetType()
.GetMethod("CreateManager",
BindingFlags.Instance | BindingFlags.NonPublic);
var method = createManagerMethod.MakeGenericMethod(typeof(string));
method.Invoke(foo, new object[] { new ServiceProvider(), new DeviceCapability() });
最后,使用适当的对象实例和参数调用Invoke
。
我不明白你为什么需要反思。你可以像下面的一样做
public interface IYourInterface //Give it a good name
{
void Instantiate(ServiceProvider serviceProvider, DeviceCapability deviceCapability);
}
public class YourClass : IYourInterface
{
public YourClass()
{
// do something if you want
}
public void Instantiate (ServiceProvider serviceProvider, DeviceCapability deviceCapability)
{
// what ever needs to be done here
}
}
private void CreateManager<T>(ServiceProvider serviceProvider, DeviceCapability deviceCapability)
where T : IYourInterface, new()
{
var instance = new T();
instance.Instantiate(serviceProvider, deviceCapability);
}
/*
Usage
*/
CreateManager<YourClass>(serviceProvider, deviceCapability);