我正试图从我正在开发的应用程序中发送图像,我有以下代码,但我不知道如何从我的/drawable文件夹中的文件创建Uri,有什么想法吗?(此时非常困惑)
@Override
public boolean onCreateOptionsMenu(Menu menu) {
getMenuInflater().inflate(R.menu.second, menu);
MenuItem shareitem = menu.findItem(R.id.menu_item_share);
myShareActionProvider = (ShareActionProvider) shareitem.getActionProvider();
myShareActionProvider.setShareIntent(createShareIntent());
ActionBar actionBar = getActionBar();
actionBar.show();
return true;
}
public Intent createShareIntent() {
image = ???
Uri uri = Uri.fromFile(image);
Intent shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.putExtra(Intent.EXTRA_STREAM, uri);
shareIntent.setType("image/png");
return shareIntent;
}
private Intent createShareIntent() {
Intent shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.setType("image/*");
Uri uri = Uri.parse("android.resource://your.package.name/" + R.drawable.image);
shareIntent.putExtra(Intent.EXTRA_STREAM, uri);
return shareIntent;
}
为了进一步回答我的问题,如果我有以下内容(数字是一个变量,根据按下的按钮而变化)。为什么以下不起作用?
public Intent createShareIntent() {
Intent intent = getIntent();
int number = intent.getIntExtra("BUTTON NUMBER", 1);
Uri imageUri = Uri.parse("android.resource://" + getPackageName() + "/"+ R.raw."BUTTON NUMBER");
Intent shareIntent = new Intent(Intent.ACTION_SEND);
shareIntent.putExtra(Intent.EXTRA_STREAM, imageUri);
shareIntent.setType("image/*");
return shareIntent;
}