为什么我要继续失败此测试?
测试立方体(1.0,1.0,1.0)将类型设置为"立方体",
宽度,长度和高度各为1.0测试反馈
预期:立方体,1.0、1.0、1.0
您的:矩形,1.0、1.0、1.0
我需要Cube类能够将其类型设置为立方体。现在,它似乎正在设置为矩形。我的主填充了一系列形状,然后我有根据每种形状的类型来计数不同类型形状的方法。当我的矩形类已经扩展形状时,我该如何将立方体定义为形状,但是我必须让我的立方体类扩展矩形。它必须是因为我还需要访问该区域以及长度和宽度。
我也有一个非常简单的接口,该接口由我的立方体实现。只是为了找到卷。我可以以某种方式利用我的界面覆盖类型吗?
找不到有关此特定问题的stackoverflow的答案。
这是我的矩形类
public class Rectangle extends Shape {
protected double width;
protected double length;
public Rectangle(double width, double length) {
super("Rectangle");
setWidth(width);
setLength(length);
}// end ctr
public final double getWidth () {return width; }
public final double getLength () {return length;}
public final void setWidth (double width) {
if (width < 0) {
System.out.println("Value could not be updated due to negative double.");
}else
this.width = width;
}// end width setter
public final void setLength (double length) {
if (length < 0) {
System.out.println("Value could not be updated due to negative double.");
}else
this.length = length;
}// end length setter
@Override
public double area() {
return length * width;
}// end area method
public double perimeter() {
return 2 * (length + width);
}// end perimeter method
@Override
public String toString() {
String str = "";
str += String.format("%10s", "Rectangle:") + " ";
str += "width: " + String.format("%.1f", width) + ", " + "length: " + String.format("%.1f", length);
str += ", " + "area: " + String.format("%.2f", area() ) + ", ";
str += "perimeter: " + String.format("%.2f", perimeter() );
return str;
}// end descriptor
}// end rect class
这是我的立方体类
public class Cube extends Rectangle implements Shape3D {
protected double height;
public Cube (double width, double length, double height) {
super(width, length);
setHeight(height);
}// end ctr
public final double getHeight () {return height;} // end get height
public final void setHeight (double height) {
if (height < 0) {
System.out.println("Value could not be updated due to negative double.");
}else
this.height = height;
}// end set height
@Override
public double volume () {
return super.area() * height;
} // end volume method
@Override
public String toString() {
String str = "";
str += String.format("%10s", "Cube:") + " ";
str += "width: " + String.format("%.1f", width) + ", " + "length: " + String.format("%.1f", length);
str += ", " + "area: " + String.format("%.2f", area() ) + ", ";
str += "perimeter: " + String.format("%.2f", perimeter() );
str += ", height: " + String.format("%.1f", height );
str += ", volume: " + String.format("%.1f", volume() );
return str;
}// end descriptor
}// end cube class
矩形类来自我的形状类,
public abstract class Shape {
protected String type;
public Shape (String type) {
setType(type);
}// end ctr
public final String getType () {return type; }
public final void setType (String type) {this.type = type;}
public abstract double area (); // end prototype
public double getArea () {return area();}
@Override
public String toString() {
String str = "";
str += type;
return str;
}// end descriptor
}// end shape class
您的立方体类使用Super来调用Rectangle的构造函数Shape类的构造函数带有字符串"矩形",基本上是您所拥有的,立方体构造函数将不允许您设置其类型的立方体。您将需要明确使用setType
方法。
您可以在Cube的构造函数中添加行
this.setType("Cube");
应该工作(尚未测试)。