我正在使用Zelle图形库,我在替换图形对象(在这种情况下,恰好是文本对象)时遇到了麻烦。
代码如下:
from Graphics import *
winName = "Window"
win = Window(winName,600,500)
win.setBackground(Color('silver'))
title = Text((300,20),"Zack's Flash Card Maker")
title.draw(win)
p1 = Rectangle((50, 100),(550,400))
p1.setFill(Color("black"))
p1.draw(win)
class FlashCard:
def __init__(self):
self.commands = {'addQuestion':self.addQuestion,'startGame':self.startGame}
self.stack = []
self.questions = {}
self.questionAnswered = False
self.questionsCorrect = 0
self.questionsIncorrect = 0
def addQuestion(self):
question = ' '.join(self.stack)
self.stack = []
answer = input(question)
self.questions[question] = answer
def startGame(self):
for question in self.questions:
if(self.questionAnswered == False):
answer=input(question)
questionText = Text((300,150),question)
questionText.setFill(Color("white"))
questionText.draw(win)
if(answer == self.questions[question]):
questionAnswer = Text((300,200),answer + " is correct!")
questionAnswer.setFill(Color("green"))
questionAnswer.draw(win)
self.questionsCorrect = self.questionsCorrect + 1
continue
else:
questionAnswer = Text((300,200),answer + " is incorrect. Study this one.")
questionAnswer.setFill(Color("red"))
questionAnswer.draw(win)
self.questionsIncorrect = self.questionsIncorrect + 1
continue
def interpret(self,expression):
for token in expression.split():
if token in self.commands:
operator = self.commands[token]
operator()
else:
self.stack.append(token)
i = FlashCard()
i.interpret('What is your dog's name? addQuestion')
i.interpret('What is your favorite thing to do? addQuestion')
i.interpret('startGame')
这实际上是我正在制作的一个迷你闪存卡程序。它接受底部的explain命令,并根据FlashCard类中的字典执行这些命令。它基本上工作:它做正确的文本对象。然而,文本开始重叠其他文本对象,因为它重新绘制。我试过移动。draw函数,但它要么根本不出现,要么重叠。
谁有什么建议?我想为每个新的抽认卡问题替换文本。谢谢!
如果您想使某些内容不可见,则需要使用undraw()命令。我建议你把它放在继续语句之前。就像
一样questionText.undraw()
questionAnswer.undraw()
或者,您可以使用del命令在完成后删除每个questionText/questionAnswer实例。这可能是一个更好的选择,因为你实际上是在释放内存,而不是存储数据而不做任何事情。
您可以使用setText方法更改文本。
的例子:
string = Text(Point(1, 1), 'original string')
sting.setText('new string')