计算机生成一个数字，用户猜测数字，不管它总是不正确的

Question

我做了一个简单的程序，用户猜测随机生成的计算机编号。为了测试程序是否正常工作，我将生成的计算机值更改为 5。但是，当我"猜测"5时，我不知何故仍然不正确。

有人可以告诉我这个代码有什么问题吗？

我尝试弄乱返回变量，但我不明白返回命令是如何工作的，所以我没有成功。

def computer_roll():
  global comproll
  comproll = random.randint(1,3)
  # comproll = 5
  user_guess()
def user_guess():
  global user
  user = input("Input a number: ")
  guess_evaluation()
def guess_evaluation():
  if user != comproll:
    print("You are incorrect.")
    again = input("Would you like to try again? ")
    if again in("y"):
      user_guess()
    elif again in ("n"):
      print("Thanks for playing.")
  elif user == comproll:
    print("You are correct.")
    again = input("Would you like to play again? ")
    if again in("y"):
      user_guess()
    elif again in ("n"):
      print("Thanks for playing.")
computer_roll() # Start```

# Expected Results: 
# When I enter 5 it should say "You are correct." and then "Would you like to play again?"
# Actual Results:
# When I enter 5 it says "You are incorrect" and then "Would you like to play again?"

Answer 1

您正在将整数与字符串进行比较，这就是为什么它永远不会正确。
尝试，user = int(input("Input a number: "))

附带说明一下，您确实不应该使用全局变量。学习使用返回，特别是因为你正在使用函数，否则使用函数根本没有意义。

下面是一个示例代码：

import numpy as np
import random
def computer_roll():
  return random.randint(4,6)
def user_guess():
  return int(input("Input a number: "))
def guess_evaluation():
  if user_guess() != computer_roll():
    print("You are incorrect.")
  else:
    print("You are correct.")
  again = input("Would you like to play again? ")
  if again in ("n"):
    print("Thanks for playing.")
  else:
    guess_evaluation()
guess_evaluation()

Answer 2

对我来说

，它有效，除了输入字段中的语法错误：

def guess_evaluation():
  if user != comproll:
    print("You are incorrect.")
    again = input("Would you like to try again? ")
    if again in("y"): # syntax error here, enter space between "in" and "('y')".
      user_guess()
    elif again in ("n"):
      print("Thanks for playing.")

Answer 3

当 comproll 是整数时，用户通常会输入字符串。您可以通过以下方式更改此设置：

user = int(input("Input a number: "))