承诺在解析/拒绝后无法运行代码

Question

i在异步函数中具有异步函数。在第二次，我必须等待承诺解决或拒绝，然后在下面运行其他代码之后。但是，如果承诺拒绝我的代码停止而没有运行其他功能。我如何修复它？

await axios.all(promises).then(res => {
  axios.patch("/url", { foo: bar }).then(async () => {
    const promises2 = arr.map(item => {
      return axios.post("/url-2", item)
    });
    await Promise.all(promises2)
      .then(() => console.log("resolved")) //this not calling ever
      .catch(() => console.log("failed")) //this not calling ever
    console.log("This console log ever not working")
  })
})

Answer 1

承诺无法正确链接，axios.patch(...)承诺不会返回。await是then和catch的句法糖，其目的是在可能的情况下摆脱嵌套功能。应该是：

const res = await axios.all(promises)
await axios.patch("/url", { foo: bar })
const promises2 = arr.map(item => {
  return axios.post("/url-2", item)
});
try {
  await Promise.all(promises2)
  console.log("resolved"))
} catch (err) {    
  console.log("failed");
}

Answer 2

您的代码顺序是错误的。当然，如果第一个承诺被拒绝，那么其余的将不会被调用。

尝试以这种方式重写您的代码：

let res = await axios.all(promises).catch(() => { console.log("failed"); return false; });
if (!res) {
    // Do something when rejected
    ....
}
// Call the 2nd promise
let res2 = await axios.path("/url", {foo: bar}).catch(() => {console.log("failed 2"); return false; });
if (!res2) {
    // Do something when the 2nd promise is rejected
    ...
}
// Call your last promise
let res3 = await Promise.all(promises2).catch(() => {console.log("failed 3"); return false; });
if (!res3) {
    // Do something if it is rejected again
    ....
}
// Otherwise, do your thing

Answer 3

尝试以下代码，它应该指出发生错误或拒绝的地方（即绝对是在运行Promise.all(promises2)之前

await axios.all(promises)
.then(res => axios.patch("/url", { foo: bar }), err => {
    throw `all(promises) failed with ${err}`;
})
.then(() => {
    const promises2 = arr.map(item => {
        return axios.post("/url-2", item);
    });
    return Promise.all(promises2)
    .then(() => console.log("resolved")) //this not calling ever
    .catch(err => {
        throw `all(promises2) failed with ${err}`;
    });
}, err => {
    throw `patch failed with ${err}`;
})
.catch(err => console.error(err));

注意，我已删除了异步/等待，因为在您发布的代码中，它完全不必要