我有以下类型的表:
表dummy1:
e_n t_s item
a t1 c
a t2 c
a t3 c
a t4 c
b p1 c
b p2 c
b p3 c
b p4 c
t1,t2,t3,t4,p1,p2,p3,p4是升序顺序的时间戳。T1,T2,T3,T4是event_name'A'的升序顺序的时间戳。P1,P2,P3,P4是event_name'B'的升序时间戳。
c是这些事件'a'和'b'的item_number。
我试图编写一个结果,结果应如下:
e_n1 e_n2 item t_s_1 t_s_2
a b c t1 p1
a b c t2 p2
a b c t3 p3
a b c t4 p4
我尝试了以下代码:
select l.e_n as e_n_1, m.e_n as e_n_2, l.item, l.t_s as t_s_a,
m.t_s as t_s_b from (
(select * from dummy where e_n = 'a') l
join
(select * from dummy where e_n = 'b') m
on l.item = m.item and l.t_s < m.t_s
需要加入l.item = m.Item,因为还有许多其他项目C1,C2,C3具有相同的结构
结果是:
e_n1 e_n2 item t_s_a t_s_b
a b c t1 p1
a b c t1 p2
a b c t1 p3
a b c t1 p4
a b c t2 p1
a b c t2 p2
a b c t2 p3
so on
如何有效地实现结果?
select min (case when e_n = 'a' then 'a' end) as e_n1
,min (case when e_n = 'b' then 'b' end) as e_n2
,item
,min (case when e_n = 'a' then t_s end) as t_s_1
,min (case when e_n = 'b' then t_s end) as t_s_2
from (select d.*
,row_number () over (partition by item,e_n order by t_s) as rn
from dummy as d
) d
group by item
,rn
+------+------+------+-------+-------+
| e_n1 | e_n2 | item | t_s_1 | t_s_2 |
+------+------+------+-------+-------+
| a | b | c | t1 | p1 |
| a | b | c | t2 | p2 |
| a | b | c | t3 | p3 |
| a | b | c | t4 | p4 |
+------+------+------+-------+-------+
首先,按时间戳按每个事件,然后在排序的表行号上加入。
尝试以下代码。
select l.e_n as e_n_1, m.e_n as e_n_2, isnull(l.item,m.item) as item, l.t_s as t_s_a,
m.t_s as t_s_b from
(select *,(row_number() over (order by t_s)) as rn from dummy where e_n = 'a') l
full join
(select *,(row_number() over (order by t_s)) as rn from dummy where e_n = 'b') m
on l.item = m.item and l.rn=m.rn