Python-嵌入在句子中的列表的打印值而不单独调用它们

Question

有没有办法打印出嵌入句子中的列表的值而不单独调用它们的值？例如，而不是这样做：

test = ["baseball","brother","sister"]
print ("Bob went out to play {} with his {} and {}.".format(test[0], test[1], test[2])).

是否有办法将其缩短为：

print ("Bob went out to play {} with his {} and {}.".format(test[0:2]))

Answer 1

正如Paul Panzer在问题评论中指出的那样，您可以在前面使用*，尽管您需要*test[0:3]而不是*test[0:2]：

test = ["baseball","brother","sister"]
print ("Bob went out to play {} with his {} and {}.".format(*test[0:3]))

这会产生：

Bob went out to play baseball with his brother and sister.