我知道这与我的指针变量有关,我的目标是将西装的颜色实现到我给定的预先存在的代码中。所以我在甲板结构下创建了一个字符指针。它将正确打印出所有内容,直到我开始洗牌,在这种情况下,我会出现分段错误。
#include <stdio.h>
#include <time.h> //time function
#include <stdlib.h> //random number generator functions
#include <string.h> //need for Linux
#define MAX 9
#define MAX_CARDS 52
#define MAX_RANKS 13
#define MAX_SUITS 4
#define COLS 2 //number of columns to display in output
//structure definition
struct card{
char *rank;
char suit[MAX];
char *color;
};
typedef struct card Card;
//array of pointers to strings for ranks
char *ranks[MAX_RANKS] = {"Ace", "Two", "Three", "Four", "Five", "Six", "Seven",
"Eight", "Nine", "Ten", "Jack", "Queen", "King"};
char *color[2] = {"(black)", "(red)"};
//two-dimensional array of strings for suits
char suits[MAX_SUITS][MAX] = {"Clubs", "Diamonds", "Hearts", "Spades"};
//[0][1] [0][2][0][3]
void initialize(Card []);
void shuffle(Card []);
void display(const Card[]);
int main(){
char newline = 'n'; //to repeat while loop
//declare an array of 52 cards
Card deck[MAX_CARDS] = {"","",""};
initialize(deck);
deck[0].color = "(black)" ;
deck[1].color = "(red)";
printf("Display an ordered deck of cards:n");
display(deck);
while('n' == newline){
printf("nshuffling deck ... nn");
shuffle(deck);
display(deck);
printf("nnWould you like to shuffle again?nIf so, press "Enter" key. If not, enter any other char. ");
newline = getchar();
}
return 0;
}
/*
initialize the deck of cards to string values
deck: an array of structure cards
*/
void initialize(Card deck[]){
int i = 0;
for(i=0;i<MAX_CARDS;i++){
deck[i].rank = ranks[i%MAX_RANKS];
strncpy(deck[i].suit, suits[i/MAX_RANKS], MAX);
}
}
/*
use the pseudo-random number generator to shuffle the cards
deck: an array of structure cards
*/
void shuffle(Card deck[]){
int swapper = 0; //index of card to be swapped
int i = 0; //counter
Card temp = {"", ""}; //temp holding place for swap
srand(time(NULL)); //seed the random numbers with current time
for(i=0;i<MAX_CARDS;i++){
//generate a pseudo-random number from 0 to 51
swapper = rand() % MAX_CARDS;
//swap current card with da swapper
temp = deck[i];
deck[i] = deck[swapper];
deck[swapper] = temp;
}
}
/*
display the deck of cards
deck: an array of structure cards
*/
void display(const Card deck[]){
int i = 0;
for(i=0;i<MAX_CARDS;i++)
{
printf("%5s of %-10s", deck[i].rank, deck[i].suit);//%5s makes "of" line up -10 makes cols.
if (strcmp(deck[i].suit, "Clubs") == 0 || strcmp(deck[i].suit, "Spades") == 0)
{
printf(" %5s", deck[0].color);
}
else
{
printf(" %5s", deck[1].color);
}
//put in a newline every %x loops
if((COLS-1) == (i%COLS)){
printf("n");
}
}
}
这是因为您的卡片具有您实际上不使用的color
,除了这里:
deck[0].color = "(black)" ;
deck[1].color = "(red)";
现在,当你洗牌deck
时,你很可能会在那里得到另一张卡,它的.color
仍然是空的,你的代码崩溃了printf("...%s...", deck[0].color);
解决方案当然是a(完全删除color
成员,b(然后将打印代码修改为:
if (strcmp(deck[i].suit, "Clubs") == 0 || strcmp(deck[i].suit, "Spades") == 0) {
printf(" (black)");
}
else {
printf(" (red) ");
}
但是,我个人会使用枚举来表示等级和花色,例如
enum Suit {
HEARTS = 0,
SPADES,
DIAMONDS,
CLUBS
};
struct Card {
enum Suit suit;
...
};
和印刷
char *suit_to_string[4] = {"Hearts", "Spades", "Diamonds", "Clubs"};
...
printf("%s", suit_to_string[deck[i].suit]);