Laravel Query Builder在按ID分组的查询中用子查询减去COUNT

Question

我在Laravel查询中遇到了这个问题。

首先，我有这个查询，我使用它来获得交易

$transactions = Transaction::select(
'customers.member_id as member_id',
DB::raw('
CASE
WHEN transactions.customer_id IS NOT NULL
THEN
customers.name 
ELSE 
"Tanpa pelanggan" 
END AS customer_name
'),
'customers.phone as customer_phone',
DB::raw('COUNT(transactions.id) as sum_qty'),
DB::raw('SUM(final_amount) as sum_amount')
)
->join('outlets', 'outlets.id', '=', 'transactions.outlet_id')
->leftJoin('customers', 'customers.id', '=', 'transactions.customer_id')
->where('outlets.company_id', '=', $companyID)
->where(function ($q) use ($permittedOutlets) {
if (!empty($permittedOutlets)) {
$q->whereIn('transactions.outlet_id', $permittedOutlets);
}
})
->where(function ($query) use ($companyID, $outletID, $startDate, $endDate, $filterData) {
if ($outletID != 0) {
$query->where('transactions.outlet_id', '=', $outletID);
}
if (!empty($startDate) && !empty($endDate)) {
if ($startDate == $endDate) {
$query->whereDate(deviceTimestamp(), '=', $startDate);
} else {
$query->whereDate(deviceTimestamp(), '>=', $startDate)
->whereDate(deviceTimestamp(), '<=', $endDate);
}
}
if ($filterData != "") {
$query->where(function ($q) use ($filterData) {
$q->where('customers.name', 'like', '%' . $filterData . '%')
->orWhere('customers.phone', 'like', '%' . $filterData . '%');
});
}
})
->isSuccessAndVoidedInDifferentDate()
->orderBy($sortField, $sort)
->groupBy('transactions.customer_id');

对于isSuccessAndVoiedInDifferentDate事务模型范围

$query->whereRaw('
CASE 
WHEN transactions.void_id IS NOT NULL
THEN 
EXISTS (
SELECT *
FROM transactions as transactions2
WHERE transactions.void_id = transactions2.id
AND transactions.created_at <> transactions2.created_at
LIMIT 1
)                
WHEN transactions.status = ''.self::STATUS_VOID.''
THEN 
EXISTS (
SELECT *
FROM transactions as transactions2
WHERE transactions.id = transactions2.void_id
AND transactions.created_at <> transactions2.created_at
LIMIT 1
)   
ELSE 
TRUE
END
');

对于原始MySql查询

SELECT 
`customers`.`member_id` AS `member_id`,
CASE
WHEN transactions.customer_id IS NOT NULL THEN customers.name
ELSE 'Tanpa pelanggan'
END AS customer_name,
`customers`.`phone` AS `customer_phone`,
COUNT(transactions.id) AS sum_qty,
SUM(final_amount) AS sum_amount
FROM
`transactions`
INNER JOIN
`outlets` ON `outlets`.`id` = `transactions`.`outlet_id`
LEFT JOIN
`customers` ON `customers`.`id` = `transactions`.`customer_id`
WHERE
`outlets`.`company_id` = 153113
AND (`transactions`.`outlet_id` IN (9164))
AND (DATE(ADDDATE(transactions.device_timestamp,
INTERVAL transactions.timezone HOUR)) >= '2020-02-01'
AND DATE(ADDDATE(transactions.device_timestamp,
INTERVAL transactions.timezone HOUR)) <= '2020-02-29')
AND CASE
WHEN
transactions.void_id IS NOT NULL
THEN
EXISTS( SELECT 
*
FROM
transactions AS transactions2
WHERE
transactions.void_id = transactions2.id
AND transactions.created_at <> transactions2.created_at
LIMIT 1)
WHEN
transactions.status = 'void'
THEN
EXISTS( SELECT 
*
FROM
transactions AS transactions2
WHERE
transactions.id = transactions2.void_id
AND transactions.created_at <> transactions2.created_at
LIMIT 1)
ELSE TRUE
END
AND `transactions`.`deleted_at` IS NULL
GROUP BY `transactions.customer_id`
ORDER BY `transactions.customer_id` ASC

所有交易都有两种不同的状态。状态为成功或无效。事务处理类型分为两类。第一类是有客户的交易，第二类是没有客户的交易。在这种情况下，没有客户的交易将被选择为"Tanpa pelanggan"。此处的所有交易都按交易分组。customer_id.

这个问题集中在上

DB::raw('COUNT(transactions.id) as sum_qty'),

在选择部分。为了更简单地理解这里的公司、网点和日期的where条款可以忽略。我正在尝试创建一个条件，其中查询中的计数将返回成功交易的计数减去按交易分组的无效交易的计数.customer_id。我有点困惑，我是否应该使用与主查询相同的where条件进行子查询，这有点重复，还是我没有找到更好的解决方案。

示例案例：数据包括：

1个作废交易剩余交易成功

预期结果：

member_id | customer_name | customer_phone| sum_qty | sum_ammount
NULL      | Sam           | 123xxxx       | 1       | 20720
NULL      | Tanpa Pelanggan| -            | 2       | 28490

实际结果：

member_id | customer_name | customer_phone| sum_qty | sum_ammount
NULL      | Sam           | 123xxxx       | 1       | 20720
NULL      | Tanpa Pelanggan| -            | 3       | 51800

我的问题是，解决这个问题的最佳方法是什么？

提前感谢！

Answer 1

找到了解决方案！

DB::raw('SUM(CASE WHEN transactions.status != 'void' THEN 1 ELSE 0 END) - SUM(CASE WHEN transactions.status = 'void' THEN 1 ELSE 0 END) as sum_qty')

它实际上是使用SUM并在SUM函数中添加CASE条件。