要计算句子中的文章？在这个程序中最后一个if语句不起作用"a"和"an"

Question

//header  
#include <bits/stdc++.h>
using namespace std;

int main(int argc, char** argv)
{
string s,s1=" ";
int i,j,flag=0,flag1=0,count=0;
getline(cin,s);
for(i=0;i<s.length();i++){
if(s[i]==' '){
flag=i;
for(j=flag1;j<flag;j++){
s1=s1+s[j];
flag1=flag+1;
}
//cout<<s1<<" ";--uncommenting this works but below if statement not working
if(s1=="a"||s1=="A"||s1=="an"||s1=="An"){
count++;
}
}
s1=" ";
}
cout<<count;
}

If语句什么都不取，只给出计数值为0

Answer 1

您的s1被初始化为空白字符，它阻止它与if语句中的字符串匹配，这些字符串都没有空白字符。

删除多余的两个空白，并将s1初始化为空字符串。

Answer 2

为了更好地让生活更轻松，您可以在std::stringstream和std::vector:的帮助下做同样的事情

#include <iostream>
#include <sstream>
#include <vector>
int main(void) {
std::string string;
std::string temp;
std::vector<std::string> words;
int counter = 0;
std::cout << "Enter a string: ";
std::getline(std::cin, string);
// a string stream to separate each word
std::stringstream ss(string);
// pushing the separated words (by space) into a dynamic array
while (ss >> temp)
words.push_back(temp);
// comparing each array of 'words' (where each separated words are stored
// as a type of 'std::string'
for (size_t i = 0, len = words.size(); i < len; i++)
if (words.at(i) == "a" || words.at(i) == "an" || 
words.at(i) == "A" || words.at(i) == "An")
counter++;
// if no articles found, i.e. the counter is zero
if (counter == 0) {
std::cout << "Sorry, there were no articles found.n";
return 0;
}
// otherwise...
std::cout << counter << " number of articles were found!n";
return 0;
}

样本输出如下：

Enter a string: A great scientist, Newton experimented something on an apple.
//             _^___________________________________________________^^_______
2 number of articles were found!

此外，请避免使用bits/stdc++.h，它既不是标准C++的一部分，也不是@ChrisMM在本文中的评论中所指示的一个好的约定。

对于命名模糊性可以忽略不计的较小程序，使用using namespace std是很好的，但在大型程序中最好避免。