具有目录假定文件名

Question

>我有一堆视频文件，我想将它们放入与视频文件同名减去扩展名（.mov）的目录中

例如，给定以下目录，我将如何编写脚本为每个与文件同名（减去.mov）的.mov文件创建一个目录，然后将.mov文件放入该目录中？

/Volumes/06a_SD_Video_01/_COLLECTIONS/TR2014_295_Walter_Reed/DER_01/ ├── TR2014_295_10_1a_PM.mov ├── TR2014_295_11_1a_DER_01.mov ├── TR2014_295_12_1a_DER_01.mov ├── TR2014_295_13_1a_DER_01.mov ├── TR2014_295_14_1a_PM.mov ├── TR2014_295_15_1a_DER_01.mov ├── TR2014_295_16_1a_DER_01.mov ├── TR2014_295_17_1a_DER_01.mov ├── TR2014_295_18_1a_DER_01.mov ├── TR2014_295_19_1a_DER_01.mov ├── TR2014_295_19_1b_DER_01.mov ├── TR2014_295_1_1a_PM.mov ├── TR2014_295_20_1a_DER_01.mov ├── TR2014_295_21_1a_PM.mov ├── TR2014_295_22_1a_DER_01.mov ├── TR2014_295_22_1b_DER_01.mov ├── TR2014_295_23_1a_DER_01.mov ├── TR2014_295_2_1a_PM.mov ├── TR2014_295_3_1a_DER_01.mov ├── TR2014_295_4_1a_DER_01.mov ├── TR2014_295_5_1a_DER_01.mov ├── TR2014_295_6_1a_DER_01.mov ├── TR2014_295_7_1a_DER_01.mov ├── TR2014_295_8_1a_DER_01.mov ├── TR2014_295_9_1a_DER_01.mov

Answer 1

这里有一种方法：

脚本：

cd "$1"
for m in *.mov; do
  d=`echo "$m" | sed 's/.mov$//'`
  mkdir "$d"
  mv "$m" "$d"
done

用法：

sh <scriptname.sh> "<directory>"

例如，

sh mov2dir.sh "/Volumes/06a_SD_Video_01/_COLLECTIONS/TR2014_295_Walter_Reed/DER_01/"