当我向tmdb.org发出xml请求时,我使用了这个
$movie_name="Dabangg 2";
$xml = simplexml_load_file("http://api.themoviedb.org/2.1/Movie.search/en/xml/accd3ddbbae37c0315fb5c8e19b815a5/"$movie_name"");
,它正在工作!!
现在我必须更改URL,因为响应是JSON而不是xml
我已经把它改成
<?php
$movie_name="Dabangg 2";
$url="http://api.themoviedb.org/3/search/movie?api_key=accd3ddbbae37c0315fb5c8e19b815a5&query=$movie_name";
$json = file_get_contents($url);
var_dump($json);
?>
但是行不通
如果你搜索
http://api.themoviedb.org/3/search/movie?api_key=accd3ddbbae37c0315fb5c8e19b815a5&query=Dabangg 2
在浏览器上,你会得到结果。
Warning: file_get_contents(http://api.themoviedb.org/3/search/movie?api_key=accd3ddbbae37c0315fb5c8e19b815a5&query=Dabangg 2) [function.file-get-contents]: failed to open stream: HTTP request failed! HTTP/1.1 400 BAD_REQUEST in /home/wwww/public_html/test/movie.php on line3
请帮帮我
Try with
urlencode($movie_name);
这个函数在编码要在a中使用的字符串时非常方便查询部分的URL,作为一种方便的方式传递变量到下一个页面。
看这个:http://codular.com/curl-with-php
下面的代码:<?php
$movie_name="Dabangg 2";
$movie_name = urlencode($movie_name);
$url="http://api.themoviedb.org/3/search/movie?api_key=accd3ddbbae37c0315fb5c8e19b815a5&query=$movie_name";
// Get cURL resource
$curl = curl_init();
// Set some options - we are passing in a useragent too here
curl_setopt_array($curl, array(
CURLOPT_RETURNTRANSFER => 1,
CURLOPT_URL => $url,
CURLOPT_USERAGENT => 'Codular Sample cURL Request'
));
// Send the request & save response to $resp
$resp = curl_exec($curl);
// Close request to clear up some resources
curl_close($curl);
var_dump($resp);
?>