我有这个类
#include "Room.h"
#include "Book.h"
#include <cstdlib>
#include <iostream>
static int book_counter = 100;
//Constructors
Book::Book() {
for(int i = 0; i < 13; i++) {
this->customer_name += 97 + rand() % 26;
}
this->arrival = rand() % 30;
this->duration = 1 + (rand() % 10);
this->ppl = 1 + rand() % 5;
this->room = nullptr;
this->book_code = book_counter++;
}
Book::Book(std::string nm, int arr, int dur, int ppl) {
this->customer_name = nm;
this->arrival = arr;
this->duration = dur;
this->ppl = ppl;
this->room = nullptr;
this->book_code = book_counter++;
}
//Methods
int Book::getArr() {
return arrival;
}
int Book::getDur() {
return duration;
}
int Book::getPpl() {
return ppl;
}
void Book::anathesi(Room* x) {
this->room = x;
}
int Book::getBookCode() {
return book_code;
}
Room* Book::getRoom() {
return room;
}
std::string Book::getCustomerName() {
return customer_name;
}
包括字符串Getter方法getCustomerName()
。当我通过第一个构造函数创建的实例在MAIN上调用此方法时,一切正常。另一方面,如果实例是通过第二个构造函数创建的,则该方法将导致分割故障。
看来customer_name
的长度无限长,因此在我尝试返回时会导致分割错误。
该方法在main
中使用以下代码:
cout << hotel.getBooks(i)->getBookCode() << " " << hotel.getBooks(i)->getCustomerName()
<< " " << hotel.getBooks(i)->getRoom()->getRoomCode() << "n";
我是新来的C ,所以请尽可能多地详细说明我的错。
课程的标题文件:
#ifndef PROJECT_BOOK_H
#define PROJECT_BOOK_H
#include <string>
class Room;
class Book {
protected:
std::string customer_name;
int book_code;
int arrival;
int duration;
int ppl;
Room* room;
public:
Book();
Book(std::string nm, int arr, int dur, int ppl);
void anathesi(Room* x);
int getArr();
int getDur();
int getPpl();
int getBookCode();
std::string getCustomerName();
Room* getRoom();
};
#endif //PROJECT_BOOK_H
在hotel.h:
private: std::vector<Book*> books;
public: Book* getBooks(int i);
在hotel.cpp中:
Book* Hotel::getBooks(int i) {
return books[i];
}
找到了问题并将其修复。我正在使用此代码创建实例:
Book obj(onoma, afiksh - 1, meres, arithmos);
我说的是分割的。我将其更改为:
Book *obj = new Book(onoma, afiksh - 1, meres, arithmos);
并解决了问题。感谢您的时间和帮助。不幸的是,我真的不知道为什么会起作用,但是一切都可以正常运行。因此,我想我必须查看new
文档。