Drupal 7:从自定义模块函数插入内容类型

Question

>我在 drupal 7 项目中的自定义模块中创建了一个表单，我需要将值插入到名为"播放器"的自定义内容类型中

这是我对表格的内容：

function custom_module_reg_form($form, $form_state){
$form['first_name'] = array(
'#type' => 'textfield',
'#attributes' => array('placeholder' => t('First Name')),
);
$form['last_name'] = array(
'#type' => 'textfield',
'#attributes' => array('placeholder' => t('Last Name')),
);
$form['email_address'] = array(
'#type' => 'textfield',
'#attributes' => array('placeholder' => t('Email Address')),
);
$form['state'] = array(
'#type' => 'textfield',
'#attributes' => array('placeholder' => t('State')),
);
$form['zip_code'] = array(
'#type' => 'textfield',
'#attributes' => array('placeholder' => t('Zip Code')),
);
$form['phone_number'] = array(
'#type' => 'textfield',
'#attributes' => array('placeholder' => t('Phone Number')),
);
$form['password'] = array(
'#type' => 'password',
'#attributes' => array('placeholder' => t('Password')),
);
$form['submit'] = array(
'#type' => 'submit',
'#value' => 'Register',
);
return $form;
}

这是提交功能，但我收到错误：

function custom_module_reg_form_submit($form, $form_state){
$first_name = $form_state['values']['first_name'];
$last_name = $form_state['values']['last_name'];
$email_address = $form_state['values']['email_address'];
$state = $form_state['values']['state'];
$zip_code = $form_state['values']['zip_code'];
$phone_number = $form_state['values']['phone_number'];
$password = encrypt($form_state['values']['password']);
$nid = db_insert('players')->fields(array(
'first_name' => $first_name,
'last_name' => $last_name,
'email_address' => $email_address,
'state' => $state,
'zip_code' => $zip_code,
'phone_number' => $phone_number,
'password' => $password,
'created' => REQUEST_TIME
))->execute();
// Save new node
$node = new stdClass();
// Set node title
$node->title = $email_address;
// set node type ex: article etc
$node->type = "players";
// set node language
$node->language = LANGUAGE_NONE;
//(1 or 0): published or not
$node->status = 0;
//(1 or 0): promoted to front page
$node->promote = 0;
node_object_prepare($node);
node_save($node);
}

我正在遵循一个示例，我在日志中看到该表不正确，但我找不到其他任何地方提供示例。我做错了什么？创建用于以编程方式从窗体插入的自定义表是否更好？谢谢，请告诉我。

Answer 1

在Drupal 7中以编程方式创建节点有两种常见的方法：不使用或使用实体API贡献的模块。

没有实体 API

$node = new stdClass();
$node->type = "players";
$node->uid = $user->uid; // makes sense to have the global $user the owner of the node
$node->language = LANGUAGE_NONE;
$node->status = 0;
$node->promote = 0;
$node->title = $email_address;
// NB: if you created the field in Drupal's UI -- it will be named "field_first_name", not "first_name"
$node->field_first_name[$node->language][]['value'] = $first_name;
// ...
$node = node_submit($node);
node_save($node);

使用实体 API(现在更常见)

// Use the Entity API to create a new object
$values = array(
'type' => 'players',
'uid' => $user->uid,
'status' => 1,
'promote' => 0,
);
$entity = entity_create('node', $values);
// Then create an entity_metadata_wrapper around the new entity.
$wrapper = entity_metadata_wrapper('node', $entity);
// Now assign values through the wrapper.
$wrapper->title->set($email_address);
$wrapper->field_first_name->set($first_name);
// ...
// Finally save the node.
$wrapper->save();

无论您选择哪种方式，都不需要db_insert('players').它实际上不起作用，因为Drupal 7不会将实体存储在单个数据库表中。

有关在代码中创建节点的详细信息，请参阅此处。