OnClick()获得地理位置不起作用

Question

问题是什么：

如果 （我围绕navigator.geolocation.getCurrentPosition(initMap, onError);缠绕function triger()，然后将其称为： <button id="btn" class="btn btn-default" onclick="triger()">）

然后

它什么都不做！

else

很好！

这是我的代码：

 <script>
  var map;
  var infowindow;
  var selecteditem="hospital";
  var radiusin=5000;
  function triger() {
      navigator.geolocation.getCurrentPosition(initMap, onError); 
}
  function onError(error){
    alert("the code is " + error.code + ". n" + "message: " + error.message);
}
  function initMap(position) {
    selecteditem= $("#selector").val();
    radiusin= $("#radius").val();    
    alert(selecteditem+"in"+radiusin);
    var longitude = position.coords.longitude;
    var latitude = position.coords.latitude;
    var latLong = new google.maps.LatLng(latitude, longitude);
    var pyrmont = latLong;// {lat: -33.867, lng: 151.195};
    map = new google.maps.Map(document.getElementById('map'), {
      center: pyrmont,
      zoom: 14
    });
    infowindow = new google.maps.InfoWindow();
    var service = new google.maps.places.PlacesService(map);
    service.nearbySearch({
      location: pyrmont,
      radius: radiusin,
      type: selecteditem
    }, callback);
  }
  function callback(results, status) {
    if (status === google.maps.places.PlacesServiceStatus.OK) {
      for (var i = 0; i < results.length; i++) {
        createMarker(results[i]);
      }
    }
  }
  function createMarker(place) {
    var placeLoc = place.geometry.location;
    var marker = new google.maps.Marker({
      map: map,
      position: place.geometry.location
    });
    google.maps.event.addListener(marker, 'click', function() {
      infowindow.setContent(place.name);
      infowindow.open(map, this);
    });
  }
</script>

和：

<div class="input-group-btn">
  <button id="btn" class="btn btn-default" onclick="triger()">
    <i class="glyphicon glyphicon-search"></i>
  </button>
</div>

Answer 1

更改

 selecteditem= $("#selector").val();

to：

 $("#selector").change(function () { slecteditem= $(this).find("option:selected").val(); }