我有以下JavaScript代码,该代码允许用户从今天的日期开始选择四天。
$(function() {
var dtToday = new Date();
var month = dtToday.getMonth() + 1;
if (dtToday.getDay() === 0) {
var day = dtToday.getDate() + 5;
} else {
var day = dtToday.getDate() + 4;
}
var year = dtToday.getFullYear();
if (month < 10)
month = '0' + month.toString();
if (day < 10)
day = '0' + day.toString();
var maxDate = year + '-' + month + '-' + day;
$('.datepicker').attr('max', maxDate);
});
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
我希望代码跳过周日,同时将未来的日子增加四个。我尝试使用IF语句,但他们只检查今天的日期是星期日,而我想达到一个情况,如果未来的4天是星期日,则应该跳过它。谢谢
如果今天是星期三(3),星期四(4),星期五(5)或星期六(6),那么您的4天窗口将包括周日(因此,您应该添加1个到几天)。这样做:
var day = dtToday.getDate() + 4;
if(dtToday.getDay() > 2) {
day += 1;
}
,您的脚本将是:
$(function(){
var dtToday = new Date();
var month = dtToday.getMonth() + 1;
var day = dtToday.getDate() + 4;
if(dtToday.getDay() > 2) {
day += 1;
}
var year = dtToday.getFullYear();
if(month < 10)
month = '0' + month.toString();
if(day < 10)
day = '0' + day.toString();
var maxDate = year + '-' + month + '-' + day;
$('.datepicker').attr('max', maxDate);
});