编写一个程序，将名称存储为 String 和数字存储为 11 个玩家的 int

Question

如何获得两场比赛每个玩家的平均分数？

编写一个程序，将名称存储为字符串，将数字存储为团队中 11 名玩家的 int。您的程序应显示/输出每个玩家在两场比赛中的平均得分。

尼克(34(、乔

伊(33(、肯(24(、瑞安(11(、乔什(3(、西蒙(6(、狄龙(10(、迈克(28(和卡梅隆(5(。

第1局： 4， 3， 3， 2， 4， 5， 6， 6， 7， 7， 8.第2局：8,4,3,3,5,5,7,8,8,9,5。

import java.util.Scanner;
import java.util.Arrays;
public class BasketballStats {
public static void main(String[] args) {
    // TODO Auto-generated method stub
    int[] jerseyNumber = {34, 33, 24, 11, 3, 13, 6, 4, 28, 10};
    String[] playerName = {"Jim", "Joe", "Ken", "James", "John", "Bud", 
"Clark", "Barry", "Jose", "Paul"};
    int[] game1 = new int[11];
    int[] game2 = new int[11];
    for (int i = 0; i < 10; i++)
            System.out.printf("Number %d: %s n" , jerseyNumber[i], 
playerName[i]);
}
public void setGame1Score() {
int[] jerseyNumber = {34, 33, 24, 11, 3, 13, 6, 4, 28, 10};
String[] playerName = {"Jim", "Joe", "Ken", "James", "John", "Bud", "Clark", 
"Barry", "Jose", "Paul"};
Scanner input = new Scanner (System.in);
    for (int i = 0; i < 10; i++) {
        System.out.println("For game 1, how many points does he score?");
        int game2 = input.nextInt();
} 
    }
}

Answer 1

当您处理单个数组中的数据属性时，事情往往会变得非常乏味。从概念上讲，在这种情况下，将玩家视为唯一对象以保存其姓名、数字和分数更有意义。

public class Player {
    private String name;
    private int number;
    private int scores[];
    private int currentGame = 0;
    public Player(String name, int number, int numGames) {
       this.name = name;
       this.number = number;
       this.scores = new int[numGames];
    }
    // Getters and Setters
    public String getName() { return name; } // Required
    public void addScore(int score) { 
        if (currentGame < scores.length) {
            scores[currentGame++] = score;
        }
    }
    public int getAverage() {
        int total = 0;
        for (int i = 0; i < currentGame; i++) {
           total += scores[i];
        }
        return total / currentGame;
    }
    @Override
    public String toString() {
        return String.format("%s (%s) : avg %d", name, number, getAverage());
    }
}

然后，您可以使用玩家的姓名、号码和他们玩的游戏数量来实例化玩家。但是，您可能希望将 Player 类视为单个游戏，并拥有一个描述每个游戏本身的对象;由10名玩家组成。对象缺少名称和数字属性的获取者/设置器。

然后，您可以创建一个数组来保存游戏的所有数据。如果您计划进行多个游戏，则可能需要一个分数数组，而不是每个玩家一个分数。

public static final String[] playerName = {"Jim", "Joe", "Ken", "James", "John", "Bud", 
"Clark", "Barry", "Jose", "Paul"}; 
public static final int[] jerseyNumber = {34, 33, 24, 11, 3, 13, 6, 4, 28, 10};
public Player[] createGame(int numGames) {
    Player[] players = new Player[10];
    for (int i = 0; i < 10; i++) {
        players[i] = new Player(playerName[i], jerseyNumber[i], numGames);
    }
    return players;
} 

然后当你需要以某种方式获得分数时。

public void getScore(Player[] players, int numGames) {
    Scanner input = new Scanner(System.in);
    for (int i = 0; i < numGames; i++) {
        System.out.println("Game " + i);
        for (Player player : players) {
            System.out.print(player.getName() + " : ");
            player.addScore(input.nextInt());
        }
    }
}
public void getAverage(Player[] players) {
    for (Player player : players) {
        System.out.println(player.toString());
    }
}